Mg(OH)2 + 2 HCl → MgCl2 + 2 H2O
(0.0500 L) x (0.500 mol/L HCl) x (1 mol Mg(OH)2 / 2 mol HCl) x (58.3197 g Mg(OH)2/mol) = 0.729 g = 729 mg Mg(OH)2
<span>(729 mg Mg(OH)2) x (5.00 mL / 400 mg) = 9.11 mL milk of magnesia</span>
I would say B(make the ramp longer). That way they will have to exert less force in order for it to the desired height. If you think about it, it is harder to go up a really steep hill vs. a hill with a gradual incline, because you have to exert less force at any one given time.
Answer:
These metals are less reactive than the neighbouring alkali metal. Magnesium is less active than sodium; calcium is less active than potassium; and so on. These metals become more active as we go down the column.
Explanation:
Magnesium is more active than beryllium; calcium is more active than magnesium; and so on.
I think it’ll be option B.
<u>Answer:</u> The molarity of
ions in the solution is 0.306 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
![\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%20of%20the%20solution%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20solute%7D%5Ctimes%201000%7D%7B%5Ctext%7BMolar%20mass%20of%20solute%7D%5Ctimes%20%5Ctext%7BVolume%20of%20solution%20%28in%20mL%29%7D%7D)
We are given:
Mass of solute
= 15.6 g
Molar mass of
= 295.6 g/mol
Volume of solution = 345 mL
Putting values in above equation, we get:
![\text{Molarity of }Cu(NO_3)_2.6H_2O=\frac{15.6g\times 1000}{295.6g/mol\times 345mL}\\\\\text{Molarity of }Cu(NO_3)_.6H_2O=0.153M](https://tex.z-dn.net/?f=%5Ctext%7BMolarity%20of%20%7DCu%28NO_3%29_2.6H_2O%3D%5Cfrac%7B15.6g%5Ctimes%201000%7D%7B295.6g%2Fmol%5Ctimes%20345mL%7D%5C%5C%5C%5C%5Ctext%7BMolarity%20of%20%7DCu%28NO_3%29_.6H_2O%3D0.153M)
As, 1 mole of
produces 1 mole of copper (II) ions and 2 moles of nitrate ions.
So, molarity of
ions = (2 × 0.153) = 0.306 M
Hence, the molarity of
ions in the solution is 0.306 M