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RUDIKE [14]
3 years ago
11

Light bends when it changes the medium because the dielectric permittivity of the material makes the path more hard to penetrate

Physics
1 answer:
bija089 [108]3 years ago
6 0

Answer:

The statement is true

Explanation:

The complete question is

Light bends when it changes the medium because the dielectric permittivity of the material makes the path more hard to penetrate

True or False

Solution

The given statement is true as it is the dielectric permittivity of the material  which does not allow light to pass through it easily.

The medium decrease the amplitude of light and hence induces change in direction without altering its velocity or frequency.

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kompoz [17]

Answer:

B) a leaf blown from a tree by the wind

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A cube is 4.4 cm on a side, with one corner at the origin. Part 1 (a) What is the unit vector pointing from the origin to the di
Sidana [21]

Answer:

(a) \hat{A} = \frac{\hat{i} + \hat{j} + \hat{k}}{\sqrt{3}}

(b) \theta = 85.44^{\circ}

Solution:

As per the question:

Side of the cube, a = 4.4 cm

Coordinates of the diagonally opposite corner, A = <4.4, 4.4, 4.4> cm

Now,

(a) To calculate the unit vector:

\hat{A} = \frac{\vec{A}}{|A|}

\hat{A} = \frac{4.4\hat{i} + 4.4\hat{j} + 4.4\hat{k}}{\sqrt{()4.4}^{2} + (4.4)^{2} + (4.4)^{2}}

\hat{A} = \frac{4.4(\hat{i} + \hat{j} + \hat{k})}{4.4\sqrt{3}}

\hat{A} = \frac{\hat{i} + \hat{j} + \hat{k}}{\sqrt{3}}

(b) To calculate the angle between the two vectors say A and A' is given by:

\vec{A}\cdot \vec{A'} = \vec{A}\vec{A'}cos\theta                      

\theta = cos^{- 1}(\frac{\vec{A}\cdot \vec{A'}}{\vec{A}\vec{A'}})        (1)

Now,

The coordinates of the diagonally opposite corner, A' is <0, 0, 1> cm

Thus

\vec{A'} = 0\hat{i} + 0\hat{j} + 1\hat{k} = \hat{k}

Now,

Using equation (1) :

\theta = cos^{- 1}(\frac{(\frac{\hat{i} + \hat{j} + \hat{k}}{\sqrt{3}})\cdot \hat{k}}{|A||A'|})

|A||A'| = (\sqrt{4.4^{2} +4.4^{2} + 4.4^{2}})(\sqrt{0^{2} + 0^{2} + 0^{2}}) = 7.261

Thus

\theta = cos^{- 1}(\frac{\frac{1}{\sqrt{3}}}{7.261})

\theta = cos^{- 1}(0.07946) = 85.44^{\circ}

4 0
4 years ago
A particle is constrained to move round a circle radius 382400km and makes a single revolution in 27.3 days. (i). Find the veloc
andreyandreev [35.5K]

The velocity and acceleration of the particle moving round the circle is;

<em><u>Velocity = 162.12 m/s</u></em>

<em><u>Velocity = 162.12 m/sAcceleration = 6.873 × 10^(-5) m/s²</u></em>

We are given;

Radius of circle; 382400 km = 382400000 m

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Velocity = 162.12 m/s

II) Acceleration is centripetal acceleration and is given by the formula;

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Read more at; brainly.com/question/12199398

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Answer:

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