A student titrated 50 cm of sulphuric acid (H2SO4)of an unknown concentration

1 answer:

3 0

No. of mol. of NaOH used: (30/1000)*0.5= 0.015mol
Mole ratio of NaOH:H2SO4= 2:1
No. of mol. of H2SO4: 0.015/2= 0.0075mol
Conc. of acid= 0.0075/(50/1000)= 0.15moldm^-3

Hope it helps, drop a thanks

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