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gayaneshka [121]
3 years ago
11

How many moles of propane gas would be present in 11 grams of the gas at standard conditions?

Chemistry
1 answer:
Akimi4 [234]3 years ago
5 0
The molar mass is usually referred to with
M
, while the mass is referred to as
m
. The amount of substance is
n
. This gives you the following relationship:
=
M
=
m
n

Since you have given (C3H8)=11 g
m
(
C
3
H
8
)
=
11

g
and you already looked up (C3H8)=44.1 gmol−1
M
(
C
3
H
8
)
=
44.1

g
m
o
l
−
1
, you can use this formula to determine (C3H8)
n
(
C
3
H
8
)
.

In this question it is quite hard to explain the use of significant figures. Those are used to imply a certain inaccuracy. Not enough information is given by the question, as of how accurate the measurement is. It is a mere exercise of converting one property into another. Here you should not worry about it.
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Misha Larkins [42]

Answer:

c

Explanation:

5 0
3 years ago
If the mass of a material is 104 grams and the volume of the material is 21 cm3, what would the density of the material be?
WITCHER [35]
Remembering that
d = m ÷ v

d = ?
m = 104 g
v = 21 cm³

Therefore:

d = 104 ÷ 21

<span>d = 4,95 g÷cm³</span>
6 0
3 years ago
Consider the gold isotope 197Au. How many electrons, protons, and neutrons are in a neutral 197Au atom?
tangare [24]

Answer:

The 197Au isotope has 79 protons, 79 electrons and 118 neutrons

Explanation:

Step 1: The isotope = 197Au

Step 2: Calculate neutrons, electrons and protons

197 = Number of protons + number of neutrons

Isotopes always have the same proton number ( is the same as the atomic number). For Gold (Au) is this 79.

The number of electrons is equal to the number of protons in a neutral atom. Since we have 79 protons, there are also 79 electrons.

All isotopes of Au have a different number of neutrons.

The number of neutrons = 197 -79 = 118 neutrons

The 197Au isotope has 79 protons, 79 electrons and 118 neutrons

6 0
3 years ago
How long, in seconds, would it take for the concentration of A to decrease from 0.860 M to 0.310 M?
kogti [31]

Answer:

2.038 seconds.

Explanation:

So, in the question above we are given the following parameters in order to solve this question. We are given a rate constant of 0.500 s^-, initial concentration= 0.860 M and final concentration= 0.310 M,the time,t =??.

Assuming that the equation for the first order of reaction is given below,that is;

A ---------------------------------> products.

Recall the formula below;

B= B° e^-kt.

Therefore, e^-kt = B/B°.

-kt = ln B/B°.

kt= ln B°/B.

Where B° and B are the amount of the initial concentration and the amount of the concentration remaining, k is the rate constant and t = time taken for the concentration to decrease.

So, we have; time taken,t = ln( 0.860/.310)/0.500.

==> ln 2.77/0.500.

==> time taken,t =2.038 seconds.

6 0
3 years ago
If a balloon containing 3000 L of gas at 39 C and 99 k Pa rises to an altitude where the pressure is 45.5 kPa and the temperatur
mihalych1998 [28]

Answer:

The new volume of the balloon will be 6046.28 L

Explanation:

Initial pressure (P1) = 99 kpa

initial volume (V1) = 3000 L

Initial temperature = 39 C = 39 + 273 = 312 K

Final pressure (P2) = 45.5 kpa

Final temperature = 16 C = 16 +273 = 289K

Final volume = ????

To calculate the final volume using the general gas equation

                  P1 V1 / T1  = P2 V2 / T2

make V2 the subject of the formular

                   V2 = 99000 ×3000× 289 / 45500×312

                   V2 = 85833000 /14196

                     V2 = 6046.28 litres

5 0
3 years ago
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