How many moles of propane gas would be present in 11 grams of the gas at standard conditions?
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Answer:
There are
Explanation:
In this problem, we need to find the number of molecules in mol of
.
The molar mass of is
No of moles = mass/molar mass
We can find mass from above formula.
Also,
No of moles = no of molecules/Avogadro number
Hence, there are
The boiling point of HF is higher than the boiling point of , and it is higher than the boiling point of
.
The boiling point is the temperature at which the pressure exerted by the surroundings upon a liquid is equalled by the pressure exerted by the vapour of the liquid.
has weak dispersion force attractions between its molecules, whereas liquid HF has strong ionic interactions between
and
ions.
Only London Forces are formed - Therefore more energy is required to break the intermolecular forces in HF than in the other hydrogen halides and so HF has a higher boiling point.
and
will only have intra-molecular attractions and there will be no hydrogen bonds present in them. As a result, their boiling point will be lower.
Hence, the boiling point of HF is higher than the boiling point of , and it is higher than the boiling point of
.
Learn more about the boiling point:
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