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PtichkaEL [24]
3 years ago
5

A group of students were investigating the force of gravity. They began by dropping a foam ball from a height of 3 meters into a

bucket of sand. The ball hit the sand in 0.306 seconds. They dropped additional balls of approximately the same diameter, but of different masses. Here is the data they collected. Based on this experiment and the collected data, what would their conclusion be?
A) Gravitational attraction is dependent on the mass of an object.
B) The greater the mass of the object the greater the acceleration due to gravity and the faster it will fall.
C) Mass does not affect the speed of falling objects assuming there is only the force of gravity acting on the objects.
D) Mass becomes a factor affecting the speed of a falling object when the object is dropped a great distance from the surface of the Earth.
Physics
1 answer:
kondaur [170]3 years ago
4 0

Answer:B

Explanation:

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Under copyright law people have to get permission to any photos you take post to social media sites?
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Yes. You must ask for permission to use, modify and/or redistribute any picture posted by another person.
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3 years ago
What is the net force acting on this box?
inn [45]
Positive 2n to the right of the box
6 0
3 years ago
3. A Tylenol has 80 mg of acetaminophen.<br> How many grams is that
denis23 [38]

\boxed{\sf 1g=1000mg}

\\ \sf\longmapsto 80g

\\ \sf\longmapsto \dfrac{80}{1000}

\\ \sf\longmapsto 0.08g

6 0
2 years ago
The carbon isotope 14C is used for carbon dating of archeological artifacts. 14C(mass 2.34×10−26kg) decays by the process known
Nookie1986 [14]

Answer:

2240.92365 m/s

Explanation:

m_1 = Mass of electron = 9.11\times 10^{−31}\ kg

v_1 = Speed of electron = 5.7\times 10^7\ m/s

p_2 = Neutrino has a momentum = 7.3\times 10^{-24}\ kg m/s

M = total mass = 2.34\times 10^{-26}\ kg

In the x axis as the momentum is conserved

Mv_x=m_1v_1\\\Rightarrow v_x=\dfrac{m_1v_1}{M}\\\Rightarrow v_x=\dfrac{9.11\times 10^{−31}\times 5.7\times 10^7}{2.34\times 10^{-26}}\\\Rightarrow v_x=2219.10256\ m/s

In the y axis

Mv_y=p_2\\\Rightarrow v_y=\dfrac{p_2}{M}\\\Rightarrow v_y=\dfrac{7.3\times 10^{-24}}{2.34\times 10^{-26}}\\\Rightarrow v_y=311.96581\ m/s

The resultant velocity is

R=\sqrt{v_x^2+v_y^2}\\\Rightarrow R=\sqrt{2219.10256^2+311.96581^2}\\\Rightarrow R=2240.92365\ m/s

The recoil speed of the nucleus is 2240.92365 m/s

3 0
3 years ago
A concave mirror has a focal length of 30.0 CM. an object is placed 15.0 CM from the mirror. what is the radius of curvature of
Nana76 [90]

Answer:

60 cm

Explanation:

We are given;

  • Focal length of a concave mirror as  30.0 cm
  • Object distance is 15.0 cm

We are required to determine the radius of curvature.

We need to know that the radius of a curvature is the radius of a circle from which the curved mirror is part.

We also need to know that the radius of curvature is twice the focal length of a curved mirror.

Therefore;

Radius of curvature = 2 × Focal length

Therefore;

Radius of curvature = 2 × 30 cm

                                 = 60 cm                                  

7 0
3 years ago
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