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Alla [95]
3 years ago
6

Two forces and are applied to an object whose mass is 11.8 kg. The larger force is . When both forces point due east, the object

's acceleration has a magnitude of 0.408 m/s2. However, when points due east and points due west, the acceleration is 0.227 m/s2, due east. Find (a) the magnitude of and (b) the magnitude of .
Physics
1 answer:
S_A_V [24]3 years ago
6 0

Can you please fill in whatever goes in the blanks ?

Without them, the question makes no sense and has no answer.

Two forces (___) and (___) are applied to an object whose mass is 11.8 kg. The larger force is (___) . When both forces point due east, the object's acceleration has a magnitude of 0.408 m/s2. However, when (___) points due east and (___) points due west, the acceleration is 0.227 m/s2, due east. Find (a) the magnitude of (___) and (b) the magnitude of (___) .

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A potato is shot out of cylinder at an angle of 17 degrees above the horizontal with an initial speed of 20 m/s. What is its max
madreJ [45]

Answer:

Maximum height, h = 1.74 meters

Explanation:

It is given that,

A potato is shot out of the cylinder. It is a case of projectile motion. The potato makes an angle of 17 degrees above the horizontal.

Initial speed with which the potato is shot out, u = 20 m/s

We have to find the maximum height of the potato. The maximum height of a projectile (h) is given by the following formula as :

h=\dfrac{u^2sin^2\theta}{2g}

Where

\theta = angle between the projectile and the surface

g = acceleration due to gravity

h=\dfrac{(20\ m/s)^2sin^2(17)}{2\times 9.8\ m/s^2}

h = 1.74 m

or h = 1.74 meters

Hence, this is the required solution.

8 0
3 years ago
nolan ryan has the record for having the speediest fastball in baseball. he could pitch one at 148 i/sec. what is that speed in
Klio2033 [76]

The speed of the ball is 101miles/hr.

A mile is a unit of length that is exactly 1,609.344 metres long. Similarly, 5,280 feet or 1,760 yards make up one mile. The mile is an imperial and common US measurement of distance.

We just have to deal with unit conversions.

One mile is 5280 feet, or  1 ft = 0.000189

The speed of the ball in miles per hour is

\frac{148ft}{1sec} . \frac{1mile}{5280ft} .\frac{60s}{1min} .\frac{60min}{1hr}

So, the speed of the ball in miles per hour is 101miles/hr.

Learn more about miles here;

brainly.com/question/23245414

#SPJ4

5 0
2 years ago
What do radio waves and microwaves have in common?
MAVERICK [17]
#3, they both come after infared and are not harmful to living cells.
6 0
4 years ago
Estimate how far apart the rays of deepest red and deepest violet light are as they exit the bottom surface. assume nred = 1.57
Harlamova29_29 [7]
We begin by noting that the angle of incidence is the one that's taken with respect to the normal to the surface in question. In this case the angle of incidence is 30. The material is Flint Glass according to the original question. The refractive indez of air n1=1, the refractive index of red in flint glass is nred=1.57, finally for violet in the glass medium is nviolet=1.60. Snell's Law dictates:
n_1sin(\theta_1)=n_2sin(\theta_2)
Where \theta_2 differs for each wavelenght, that means violet and red will have different refractive indices in the glass.
In the second figure provided details are given on which are the angles in question, \Delta x is the distance between both rays.
\theta_{2red}=Asin(\frac{sin(30)}{1.57})\approx 18.5705
\theta_{2violet}=Asin(\frac{sin(30)}{1.60})\approx 18.21
At what distance d from the incidence normal will the beams land at the bottom?
For violet we have:
d_{violet}=h.tan(\theta_{2violet})\approx 0.0132m
For red we have:
d_{red}=h.tan(\theta_{2red})\approx 0.0134m
We finally have:
\Delta x=d_{red}-d_{violet}\approx2.8\times10^{-4}m


6 0
3 years ago
HELPPP IM DESPERATE
damaskus [11]

the first one cuz I know

5 0
3 years ago
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