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evablogger [386]
3 years ago
11

A householder has a 10.8 kW electric shower installed in the bathroom. Calculate the current drawn from the mains electricity su

pply by the shower.
Physics
1 answer:
emmasim [6.3K]3 years ago
5 0

Answer:

90 A

Explanation:

Applying,

P = VI.............. Equation 1

Where P = Power, V = Supply voltage, I = current.

Make I the subject of the equation

I = P/V.............. Equation 2

From the question,

Assuming the Voltage of the main electric supply is 120 V

Given: P = 10.8 kW = 10800 W, V = 120 V (household voltage)

Substitute these values into equation 2

I = 10800/120

I = 90 A

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steposvetlana [31]

Answer:

Impedance, Z = 107 ohms

Explanation:

It is given that,

Resistance, R = 100 ohms

Inductance, L=800\ mH=800\times 10^{-3}\ H=0.8\ H

Capacitance, C=10\ \mu F=10\times 10^{-6}\ F=10^{-5}\ F

Frequency, f = 60 Hz

Voltage, V = 120 V

The impedance of the circuit is given by :

Z=\sqrt{R^2+(X_C-X_L)^2}...........(1)

Where

X_C is the capacitive reactance, X_C=\dfrac{1}{2\pi fC}

X_C=\dfrac{1}{2\pi \times 60\times 10^{-5}}=265.65\ \Omega

X_L is the inductive reactance, X_L={2\pi fL}

X_L={2\pi \times 60\times 0.8}=301.59\ \Omega

So, equation (1) becomes :

Z=\sqrt{(100)^2+(265.65-301.59)^2}

Z = 106.26 ohms

or

Z = 107 ohms

So, the impedance of the circuit is 107 ohms. Hence, this is the required solution.

8 0
3 years ago
AP physics Will give brainliest to correct answer.
rjkz [21]

Answer:

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Answer:

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How can wind put off fire?
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