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4 years ago

What evidence can you cite to support the claim that the frequency of light does not change upon reflection?

1 answer:

soldier1979 [14.2K]4 years ago

8 0

Answer: The color of an image is equal to the color of the item forming the picture. When you have a take a observe your self in a mirror, the color of your eyes would not alternate. The reality that the color is equal is proof that the frequency of light would not alternate upon reflection.

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A woman can row a boat at 4.0 mph is still water.

vovikov84 [41]

Answer:

1) $\theta=120^{\circ}$ from the positive x-axis.

2) $t=20\ min$

Explanation:

Given:

speed of rowing in still water, $v=4\ mph$

speed of water stream, $v_s=2\ mph$

we know that the direction of resultant of the two vectors is given by:

$tan\ \beta=\frac{v.sin\ \theta}{v_s+v.cos\ \theta}$

where:

$\beta=$ the angle of resultant vector from the positive x-axis.

$\theta =$ angle between the given vectors

When the rower wants to reach at the opposite end then:

$\beta =90^{\circ}$

so,

$tan\ 90^{\circ}=\frac{v.sin\ \theta}{v_s+v.cos\ \theta}$

$\Rightarrow v_s+v.cos\ \theta=0$

$2+4\times cos\ \theta=0$

$cos\ \theta=-\frac{1}{2}$

$\theta=120^{\circ}$ from the positive x-axis.

Now the resultant velocity of rowing in the stream:

$v_r=\sqrt{v^2+v_s^2+2\times v.v_s.cos\ \theta}$

$v_r=\sqrt{4^2+2^2+2\times 4\times 2\times cos\ 120}$

$v_r=12\ mph$

Therefore time taken to cross a 4 miles wide river:

$t=\frac{4}{12}$

$t=\frac{1}{3}\ hr$

$t=20\ min$

8 0

3 years ago

A large, 60 turn circular coil of radius 10.0 cm carries a current of 4.2 A. At the center of the large coil is a small 20 turn

Eddi Din [679]

To solve this problem we apply the concepts related to the electric torque generated by the electromagnetic field. Mathematically this Torque can be written under the following relation

$\tau = NIAB sin\theta$

Here,

N = Number of Turns

I = Current

A = Area

B = Magnetic Field

The maximum torque will be reached when the angle is 90 degrees, then we will have the following relation,

$\theta = 90\°C$

Magnetic Field is given at function of the number of loops, permeability constant at free space at the perimeter, then

$B = \frac{N\mu_0 I}{2\pi r}$

$B = \frac{(60)(4\pi * 10^{-7})(4.2)}{2\pi (0.1)}$

$B = 5.04*10^{-4}T$

Replacing at the first equation we have,

$T = (20)(\pi (0.005)^2)(1)(5.04*10^{-4})$

$T = 7.91*10^{-7}N\cdot m$

4 0

3 years ago

Um comentarista de futebol certa vez comentou:"A bola bateu na trave e voltou duas vezes mais forte". Sabendo que quando a bola

ryzh [129]

Answer:

Por ela ter batido na trave, não tem como voltar 2x mais forte, por que toda ação correspondente a uma reação de igual intensidade, mas que atua no sentido oposto

Explanation:

7 0

3 years ago

Who received a patent for the first automobile

madreJ [45]

Ford was the first person to receive this patent.

8 0

3 years ago

The distance between the lenses in a compound microscope is 18 cm. The focal length of the objective is 1.5 cm. If the microscop

Blababa [14]

Answer:

The focal length of eye piece is 6.52 cm.

Explanation:

Given that,

Angular Magnification of the microscope M = -46

the distance between the lens in microscope L= 16 cm

The focal length of objective f₀ = 1.5 cm

Normal near point N = 25 cm

Have to find focal length of eye piece f ₙ =?

The angular magnification is given by

M ≈ - (L-fₙ)N/f₀fₙ

Rearranging for fₙ

fₙ =L(1 - Mf₀/N)⁺¹

=18/2.76

fₙ = 6.52 cm

The focal length of eye piece is 6.52 cm.

6 0

3 years ago