Answer:
Water and Salt are the products of simplest types of acid-base reactions.
Examples:
Base Acid Salt Water
NaOH + HCl → NaCl + H₂O
2 NaOH + H₂SO₄ → Na₂SO₄ + 2 H₂O
NaOH + CH₃CO₂H → CH₃COONa + H₂O
In all theses simple reactions the base (i.e. OH⁻) abstracts proton from the acid and forming a conjugate base with negative charge. Thus the negative charged conjugate base forms a salt with positively charged sodium ions.
At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 39 mL.
<h3>What is Avogadro's law?</h3>
Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."
It is expressed as;
V₁/n₁ = V₂/n₂
Given the data in the question;
- Initial amount of gas n₁ = 5.4moles
- Initial volume v₁ = 34mL = 0.034L
- Final amount of gas n₁ = 6.2moles
We substitute our values into the expression above.
V₁/n₁ = V₂/n₂
V₁n₂ = V₂n₁
V₂ = V₁n₂ / n₁
V₂ = (0.034L × 6.2moles) / 5.4moles
V₂ = 0.2108molL / 5.4mol
V₂ = 0.039L
V₂ = 39 mL
Therefore, at constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 39 mL.
Learn more about Avogadro's law here: brainly.com/question/15613065
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Answer:
Moisture content in wet basis = 47.4 %
Explanation:
<u>Moisture content expresses the amount of water present in a moist sample.</u> <u>Dry basis and wet basis are widely used to express moisture content. </u>
The next equation express the moisture content in wet basis:
<em>where, : moisture content in wet basis and </em>
<em> : moisture content in dry basis </em>
We now calculate the moisture content in wet basis:
= 0.474 = 47.4 % wet basis
Have a nice day!
Heat lost (metal)=Heat gained (water)
Q in = Q out
So energy gained by the water = 1200 J