All categories

3 years ago

The weight of a box is 1200 Newton if it exerts a pressure of 800 Pascal calculate the area

Physics

1 answer:

fomenos3 years ago

5 0

Answer:

1.5m2

Explanation:

P=F/A. So here the force is given and the pressure is also given so you make the area the subject since that is what u are looking for

You might be interested in

Consider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of 60 and 3

Scilla [17]

Explanation:

Given that,

Angle by the normal to the slip α= 60°

Angle by the slip direction with the tensile axis β= 35°

Shear stress = 6.2 MPa

Applied stress = 12 MPa

We need to calculate the shear stress applied at the slip plane

Using formula of shear stress

$\tau=\sigma\cos\alpha\cos\beta$

Put the value into the formula

$\tau=12\cos60\times\cos35$

$\tau=4.91\ MPa$

Since, the shear stress applied at the slip plane is less than the critical resolved shear stress

So, The crystal will not yield.

Now, We need to calculate the applied stress necessary for the crystal to yield

Using formula of stress

$\sigma=\dfrac{\tau_{c}}{\cos\alpha\cos\beta}$

Put the value into the formula

$\sigma=\dfrac{6.2}{\cos60\cos35}$

$\sigma=15.13\ MPa$

Hence, This is the required solution.

3 0

3 years ago

What unit is used to measure the amount of energy used?

NNADVOKAT [17]

Answer: Joule

Explanation:

5 0

3 years ago

Someone answer these questions please???

chubhunter [2.5K]

Yeah sure someone else in answering rn

8 0

3 years ago

Read 2 more answers

The atomic radii of Mg2+ and F- ions are 0.072 and 0.133 nm, respectively.(a) Calculate the force of attraction between these tw

timurjin [86]

Answer:

$1.09527\times 10^{-8}\ N$

Explanation:

$q_1$ = Mg ion = $+2q$

$q_2$ = F ion = $-q$

q = Charge of electron = $1.6\times 10^{-19}\ C$

r = Distance between ions = $0.072+0.133\ nm$

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

Electrical force is given by

$F=-\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=-\dfrac{8.99\times 10^9\times 2\times 1.6\times 10^{-19}\times -1\times 1.6\times 10^{-19}}{[(0.072+0.133)\times 10^{-9}]^2}\\\Rightarrow F=1.09527\times 10^{-8}\ N$

The attractive force is $1.09527\times 10^{-8}\ N$

8 0

3 years ago

The pressure gauge shown below has a spring for which k = 60 N/m, and the area of the piston is 0.50 cm2. Its right end is conne

kicyunya [14]

Answer:

0.025 m

0.059166 m

Explanation:

P = Pressure

A = Area

x = Compression of spring

Force is given by

$F=PA\\\Rightarrow F=30000\times 0.5\times 10^{-4}\\\Rightarrow F=1.5\ N$

From Hooke's law

$F=kx\\\Rightarrow x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{1.5}{60}\\\Rightarrow x=0.025\ m$

The spring is compressed 0.025 m

In the second case

$F_1=1.5\ N$

$F_2=101000\times 0.5\times 10^{-4}\\\Rightarrow F_2=5.05\ N$

Net force would be

$F=F_2-F_1\\\Rightarrow F=5.05-1.5\\\Rightarrow F=3.55\ N$

Compression would be

$x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{3.55}{60}\\\Rightarrow x=0.059167\ m$

The compression of the spring is 0.059166 m

8 0

3 years ago

The weight of a box is 1200 Newton if it exerts a pressure of 800 Pascal calculate the area​

The weight of a box is 1200 Newton if it exerts a pressure of 800 Pascal calculate the area