All categories

3 years ago

5. Identify the reactants in this chemical equation: 2H3PO4 → HAP20, +H2O

Physics

1 answer:

mixas84 [53]3 years ago

4 0

Answer:

H=Hydrogen, PO4=Phosphate

Explanation:

Reactions are on the left side of arrow and products are on the right side of arrow.

You might be interested in

Red light of wavelength 633 nmnm from a helium-neon laser passes through a slit 0.360 mmmm wide. The diffraction pattern is obse

777dan777 [17]

Answer:

Δy= 5,075 10⁻⁶ m

Explanation:

The expression that describes the interference phenomenon is

d sin θ = (m + ½) λ

As the observation is on a distant screen

tan θ = y / x

tan θ= sin θ/cos θ

As in ethanes I will experience the separation of the vines is small and the distance to the big screen

tan θ = sin θ

Let's replace

d y / x = (m + ½) λ

The width of a bright stripe at the difference in distance

y₁ = (m + ½) λ x / d

m = 1

y₁ = 3/2 λ x / d

Let's use m = 1, we look for the following interference,

m = 2

y₂ = (2+ ½) λ x / d

The distance to the screen is constant x₁ = x₂ = x₀

The width of the bright stripe is

Δy = λ x / d (5/2 -3/2)

Δy = 630 10⁻⁹ 2.90 /0.360 10⁻³ (1)

Δy= 5,075 10⁻⁶ m

8 0

3 years ago

Six seconds after starting from rest, a car is moving at 15 m/s. What is the car's

Sidana [21]

Answer:

2.5 m/s²

Explanation:

a = ∆v/∆t = (15 m/s)/(6 s) = (15/6) m/s² = 2.5 m/s²

7 0

3 years ago

How does climate change affect the ocean??

Debora [2.8K]

It raises the water level because of the melting glaciers.

6 0

4 years ago

A wheel is rotating about a fixed axis with constant angular acceleration 3 rad/s². At different moments, its angular speed is -

meriva

b and e are the largest and equal in magnitude. $w*2R = (2)(2)R = 4R$

A and d are next. aR = (3rad/s2)R = 3R

c is zero. wR = v = 0; Angular acceleration is zero.

<h3>What is angular acceleration?</h3>

The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second. Therefore, = d d t. Rotational acceleration is another name for angular acceleration.
Angular velocity divided by acceleration time can be used to define angular acceleration. (t). As an alternative, use pi times the drive speed (n) divided by the acceleration time (t) times 30. Radians per second squared (Rad/sec2) is the standard SI unit for rotational acceleration resulting from this equation.
To calculate angular velocity, we can use one of three formulas. The definition itself provides the first. Theta = position angle, t = time, and w = angular velocity, where w = angular velocity, theta = position angle, and t = time. Angular velocity is the rate of change of an object's position angle with respect to time.
The symbol for angular acceleration is, and it is measured in rad/s2, or radians per second square.

If two items are equal, show them as equal in your ranking. If a quantity is equal to zero, show that fact in your ranking:

b and e are the largest and equal in magnitude. $w*2R = (2)(2)R = 4R$

A and d are next. aR = (3rad/s2)R = 3R

c is zero. wR = v = 0; Angular acceleration is zero.

To learn more about angular acceleration, refer to:

brainly.com/question/20912191

#SPJ4

8 0

2 years ago

A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 10 m from the takeoff point. you may want t

Stells [14]

<u>Answer:</u>

Takeoff speed of Kangaroo = 12.91 m/s

<u>Explanation:</u>

The distance reached by Kangaroo = 10 meter

Angle at which it jumps = 18°

The motion of Kangaroo is like a projectile, the distance traveled is the range of projectile.

Range of projectile = Time taken for the projectile to reach ground* Horizontal velocity

Time taken for the projectile to reach ground:

Time taken = Two times of the time taken for the projectile to reach maximum height

Time taken for the projectile to reach maximum height = Vertical speed / Acceleration = u sin θ/g

Time taken for the projectile to reach ground = 2 u sin θ/g

So Range of projectile = $ucos\theta*\frac{2usin\theta}{g} =\frac{u^2sin2\theta}{g}$

We have Range = 10 meter, θ = 18⁰

Substituting

$10=\frac{u^2sin(2*18)}{9.8}\\ \\ u^2= 166.73\\ \\ u=12.91 m/s$

Takeoff speed of Kangaroo = 12.91 m/s

3 0

3 years ago

Read 2 more answers