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NeTakaya
3 years ago
12

Use the drop-down menus to name the following structures. DONE

Chemistry
1 answer:
tankabanditka [31]3 years ago
6 0

Answer:

3–heptene or Hept–3–ene.

Explanation:

To name the compound given in the question above, we must determine the following:

1. Identify the functional group of the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached to the compound.

4. Locate the position of the double bond (i.e the functional group) by giving it the lowest possible count.

5. Combine the above to obtain the name of the compound.

Now, we shall obtain the name of the compound as follow:

1. The compound contains double bond. Hence the compound is an alkene.

2. The longest continuous carbon chain is 7 i.e heptene.

3. No substituent group is attached to the compound.

4. The double bond is located at carbon 3 since counting from the right gives the lowest count for the double bond.

5. The name of the compound is:

3–heptene or Hept–3–ene

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Write a balanced net ionic equation showing only the particles involved in the reaction and balancing the charges.Pb(s) AgNO3aq)
Alexus [3.1K]

Answer:

Pb(s) + 2Ag+(aq) → 2Ag(s) + Pb2+(aq)

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Step 1: The unbalanced equation

Pb(s) + AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

Step 2: Balancing the equation

Pb(s) + AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

On the right side we have 2x NO3, on the left side we have 1x NO3.

To balance the amount of NO3 on both sides, we have to multiply AgNO3 (on the left side) by 2.

Pb(s) + 2AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

On the left side we have 2x Ag, on the right side we have 1x Ag.

To balance the amount of Ag on both sides, we have to multiply Ag (on the right side) by 2. Now the equation is balanced.

Pb(s) + 2AgNO3(aq) → 2Ag(s) + Pb(NO3)2(aq)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will look like this

Pb(s) + 2Ag+(aq) → 2Ag(s) + Pb2+

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