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Ugo [173]
2 years ago
5

What is the momentum of a 1.5 * 10 ^ 3 - kil kilogram car as it travels at 30. meters per second due east for 60. seconds ?

Physics
1 answer:
serg [7]2 years ago
6 0

Answer:

45000kgm/s due east

Explanation:

Given parameters:

Mass of the car  = 1.5 x 10³kg

Velocity  = 30m/s

Time taken  = 60s

Unknown:

Momentum  = ?

Solution:

Momentum is the quantity of motion a body possess,

     Momentum  = mass x velocity

So;

  Momentum  = 1.5 x 10³ x 30  = 45000kgm/s due east

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Plz help 20 points!!
vazorg [7]

Answer:

1-d

2- a

3-e

4-b

5-c

This is the correct sequence

5 0
2 years ago
Determine the kinetic energy of a 10 Kg roller coaster car that is moving with a speed of 2m/s.
skelet666 [1.2K]

In this question all required information's are already provided. Based on these details the answer to the question can be easily determined. Let us now write down all the information's that are already given.

Mass of the roller coaster = 1000 kg

Velocity of the roller coaster = 20.0 m/s

We know the formula for finding the kinetic energy is

Kinetic energy = 0.5 * mass * (velocity) ^2

                      = 0.5 * 1000 * (20)^2

                      = 0.5 * 1000 * 400

                      = 200000 Joules

So the Kinetic energy of the roller coaster is 200000 joules.

i hope this helps you friend good luck on your quiz or lesson

6 0
1 year ago
Question 4. A tuning fork ‘A’ produces 6 beats/sec with another fork ‘B’ of un-known frequency. On
8090 [49]

Clever problem.

We know that the beat frequency is the DIFFERENCE between the frequencies of the two tuning forks.  So if Fork-A is 256 Hz and the beat is      6 Hz, then Fork-B has to be EITHER 250 Hz OR 262 Hz.  But which one is it ?

Well, loading Fork-B with wax increases its mass and makes it vibrate SLOWER, and when that happens, the beat drops to 5 Hz.  That means that when Fork-B slowed down, its frequency got CLOSER to the frequency of Fork-A ... their DIFFERENCE dropped from 6 Hz to 5 Hz.

If slowing down Fork-B pushed it CLOSER to the frequency of Fork-A, then its natural frequency must be ABOVE Fork-A.

The natural frequency of Fork-B, after it gets cleaned up and returns to its normal condition, is 262 Hz.  While it was loaded with wax, it was 261 Hz.

4 0
3 years ago
If there are 20 Earthworms in a garden that covers 5 square meters, what is the population density of the earthworms?
hodyreva [135]

I think, I do think.. that it is D.

Wouldn't it be simple to divide 5 from 20, that would equal 4.

4 earthworms per square meter.

3 0
3 years ago
Read 2 more answers
A wire loop with 70 turns is formed into a square with sides of length ???? . The loop is in the presence of a 1.20 T uniform ma
Oksi-84 [34.3K]

Answer:

l= 3.002 cm

Explanation:

Given that

n= 70 turns

B= 1.2 T

θ= 15°

I= 1.5 A

τ = 0.0294 N⋅m

Lets take length of sides is l.

We know that

τ  = n I A B sin θ

Area of square ,A= l²

Now by putting the value

τ  = n I A B sin θ

0.0294  = 70 x  1.5 x  l² x  1.2 x  sin 15°

l² = 0.000901 m²

l² = 9.01 cm²

l= 3.002 cm

3 0
3 years ago
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