Question

A 0.1 kg baseball is thrown with a velocity of 45 m/s. If a 85 kg catcher catches the ball, with what speed does he move after the catch? ​

Answer 1

Answer:

v₂ = 0.0529 [m/s]

Explanation:

To solve this problem we must use the principle of conservation of linear momentum, where momentum is conserved before or after launching the baseball. Momentum is defined as the product of mass by Velocity.

$P =m*v$

where:

P = lineal momentum [kg*m/s]

m = mass = 0.1 [kg]

v = velocity of the ball = 45 [m/s]

$P = 0.1*45\\P=4.5[kg*m/s]$

Now when the catcher receives the ball it will carry the same momentum as when it was thrown.

$4.5=85*v_{2}\\v_{2}=0.0529[m/s]$