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nlexa [21]
3 years ago
12

I’m sorry I’m confused can you help me?

Chemistry
1 answer:
Amanda [17]3 years ago
5 0

Answer:

2 electrons

Explanation:

The first principal energy level contains only an s sublevel; therefore, it can hold a maximum of two electrons.

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What kind of intermolecular forces act between two ammonia molecules
iragen [17]

Answer:

extensive hydrogen bonding

Explanation:

The high boiling points of water, hydrogen fluoride (HF) and ammonia (NH3) is an effect of the extensive hydrogen bonding between the molecules. The London dispersion force is caused by random and temporary changes in the polarity of atoms, caused by the location of the electrons in the atoms' orbitals.

Hope this helps :)

6 0
2 years ago
If an isotope of oxygen has 8 protons, 10 neutrons, and 8 electrons, its mass number is_______.
melamori03 [73]

Answer:

mass number = 18

Explanation:

The mass number is the total amount of protons and neutrons in an atom. Therefore, if there are 8 protons and 10 neutrons, the mass number is 18 (8 + 10 = 18).

4 0
2 years ago
Use the solubility rules from the Lab 4 introduction and your knowledge of qualitative separation schemes from the lab to answer
cluponka [151]

Answer:

a13+a13

Explanation:

4 0
3 years ago
1) What is the name of the following Covalent Compound:<br> N2O6
Mars2501 [29]
Iconic +covalent is the answer to this
8 0
3 years ago
Given pH = 3.50 Find: [H3O+] and [OH-] Is this acidic, basic or neutral?
lys-0071 [83]

Answer:

Explanation:

Given parameters:

           pH = 3.50

Unknown:

    concentration of [H₃0⁺] = ?

    concentration of [OH⁻] = ?

Solution:

In order to find the unknown, we use some simple expressions which best explains the pH scale and the equilibrium systems of aqueous solutions.

         pH = -log₁₀[H₃O⁺]

         [H₃O⁺] = inverse log₁₀ (-pH) = 10^{-pH} = 10^{-3.5}

          [H₃O⁺] = 3.2 x 10⁻⁴moldm⁻³

       

For the  [OH⁻]:

       we use : pOH = -log₁₀ [OH⁻]

     Recall: pOH + pH = 14

                  pOH = 14 - pH = 14 - 3.5 = 10.5

  Now we plug the value of pOH into pOH = -log₁₀ [OH⁻]

                                   [OH⁻] = 10^{-pOH}

                        [OH⁻] = 10^{-10.5} = 3.2 x 10⁻¹¹moldm⁻³

The solution is acidic as the concentration of H₃0⁺ is more than that of the OH⁻ ions.

                   

8 0
3 years ago
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