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GenaCL600 [577]

3 years ago

14

If anyone knows manufacturing plz help

1 answer:

sveta [45]3 years ago

8 0

Answer:

I don't know ask my dad he would

Explanation:

but I can't ask him because he went to get milk and forgot to come back

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"Transformer is used to change the voltage".

LUCKY_DIMON [66]

Hi! transformer is used to change the voltage through electromagnetic induction.

6 0

2 years ago

Dangerous of overloading in a circuit,

Leto [7]

Answer:

Exceeding the rated load for the circuit wiring causes the circuit breaker to trip, shutting off the power to the entire circuit. If there were no breaker in the circuit, an overload would cause the circuit wiring to overheat, which could melt the wire insulation and lead to a fire

Explanation:

need thanks and make me brainiest if it helps you

6 0

3 years ago

Air enters a 200 mm diameter adiabatic nozzle at 195 deg C, 500 kPa and 100 m/s. It exits at 85 kPa. If the exit diameter is 158

ahrayia [7]

Answer:

$v_2 = 160.23 m/s$

$T_2 = 475.797 k$

Explanation:

given data:

Diameter = $d_1 = 200mm$

$t_1 =195 degree$

$p_1 =500 kPa$

$v_1 = 100m/s$

$p_2 = 85kPa$

$d_2 = 158mm$

from continuity equation

$A_1v_1 = A_2v_2$

$v_2 = \frac{\frac{\pi}{4}d_1^2 v_1^2}{\frac{\pi}{4}d_2^2}$

$v_2 = \frac{d_2v_1}{d_2^2}$

$v_2 = [\frac{d_1}{d_2}]^2 v_1$

$= [\frac{0.200}{0.158}]^2 \times 100$

$v_2 = 160.23 m/s$

by energy flow equation

$h_1 + \frac{v_1^2}{2} +gz_1 +q =h_2 + \frac{v_2^2}{2} +gz_2 +w$

$z_1 =z_2$ and q =0, w =0 for nozzle

therefore we have

$h_1 -h_2 =\frac{v_1^2}{2} -\frac{v_2^2}{2}$

$dh = \frac{1}{2} (v_1^2 -v_2^2)$

but we know dh = Cp dt

hence our equation become

$Cp(T_2 -T_1) = \frac{1}{2} (v_1^2 -v_2^2)$

$Cp (T_2 -T_1) = 7836.94$

$(T_2 -T_1) = \frac{7836.94}{1.005*10^3}$

$(T_2 -T_1) = 7.797$

$T_2 = 7.797 +468 = 475.797 k$

8 0

3 years ago

A manager who focuses on the employees who enable a company to do business is human resource management. True True False False

nydimaria [60]

Answer:

False.

Explanation:

6 0

3 years ago

The moisture in hot, humid, stagnant air surrounding a cold-water pipeline continually diffuses to the cold surface where it con

VladimirAG [237]

Answer:

The simplest differential form of Fick's flux equation for water vapor is

$\frac{1}{r} \frac{d}{dr} (rN_{rA} )=0$

Explanation:

Fick's law has to do with the density of the particles is proportional to their concentration gradient. For this question some assumptions will be taken into account:

-The pipe is considered to be very long and diffusion only occurs in the r direction.

-The reaction is not homogeneous, therefore RA = 0

-The concentration of the component A is constant

-No mixing, only diffusion

Due to the complexity of the terms used in solving the Fick equation, the solution is found in the attached file.

6 0

3 years ago