<h3>
Answer:</h3>
733 g CO₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] 2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O
[Given] 5.55 mol C₃H₇OH
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol C₃H₇OH → 6 CO₂
Molar Mass of C - 12.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol
<u>Step 3: Stoichiometry</u>
- Set up conversion:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
732.767 g CO₂ ≈ 733 g CO₂
The mass of CO2 produced by 26g of acetylene is 88g.
Given ,
In an oxyacetylene torch, acetylene gas (ethyne; HCCH) burns to produce carbon dioxide and water vapour.
The acetylene combustion reaction is given by,
H2O + HCCH + 5/2 O=O 2CO2
Heat of reaction for acetylene combustion = 1259kj/mol
CO2 has a molecular mass of 44g/mol.
2 moles of CO2 have a molecular mass of 88g.
On combustion, 1 mole of acetylene yields 2 moles of CO2.
Thus, 26g of acetylene produces 88g of CO2 when burned.
As a result, the mass of carbon dioxide produced by 26g of acetylene is 88g.
Learn more about acetylene here :
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i think its C pls dont get mad if it is wrong
a balanced chemical equation occurs when the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.
<h3>A. an acidic............</h3>