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SCORPION-xisa [38]
3 years ago
7

Plsss help ! Based on the information in the table, which pair of elements would likely form the least polar bonds with each oth

er?
A. oxygen and phosphorus

B. phosphorus and bromine

C. nitrogen and oxygen

D. bromine and nitrogen
Chemistry
2 answers:
raketka [301]3 years ago
4 0

Answer:

please mark me as brainlest

Explanation:

A is the answers for the question

Inessa [10]3 years ago
3 0

Answer:

<em>OXYGEN</em><em> AND</em><em> </em><em>PHOSPHORUS</em><em> </em><em>IS </em><em>YOUR</em><em> ANSWER</em>

<em>PLS</em><em> MARK</em><em> ABOVE</em><em> GUY</em><em> ANSWER</em><em> AS</em><em> BRAINLIEST</em>

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The common ion effect for ionic solids (salts) is to decrease the solubility of the ionic compound in water significantly. Expla
MrMuchimi

Answer:

Explanation has been given below.

Explanation:

Let's consider solubility equilibrium of an ionic insoluble compound e.g. BaSO_{4}

BaSO_{4}\rightleftharpoons Ba^{2+}+SO_{4}^{2-}

Equilibrium constant of this solubility equilibrium is represented in terms of solubility product (K_{sp}) which is expressed as-

K_{sp}=[Ba^{2+}][SO_{4}^{2-}]

Now, if we add an ionic salt e.g. Na_{2}SO_{4} with a common ion SO_{4}^{2-} then concentration of SO_{4}^{2-} increases.

But, at a constant temperature, K_{sp} is constant.

Therefore, to keep K_{sp} constant, excess amount of SO_{4}^{2-} will combine with free Ba^{2+} ion in solution and produce BaSO_{4}.

Hence, as a whole, solubility of BaSO_{4} decreases.

3 0
4 years ago
Some examples of physical properties(something I can test for that doesn’t change what the substance is)are
melisa1 [442]

Answer:

v

Explanation:

7 0
3 years ago
Neon is compressed from 100 kPa and 16°C to 500 kPa in an isothermal compressor. Determine the change in the specific volume and
Viktor [21]

Answer:

\Delta v=-0.952m^3/kg

\Delta h=0

Explanation:

In this case, since neon could be considered as an ideal gas, the specific volumes at the first and second state are respectively:

v_1=\frac{Rg*T_1}{p_1}=\frac{0.4119kJ/kg*K*289.15}{100kPa} =1.19m^3/kg\\

v_2=\frac{Rg*T_2}{p_2}=\frac{0.4119kJ/kg*K*289.15}{500kPa} =0.238m^3/kg\\

Thus, the change in the specific volume turns out:

\Delta v=v_2-v_1=0.238m^3/kg-1.19m^3/kg\\\Delta v=-0.952m^3/kg

Which value has sense for the compression.

In addition, the specific enthalpy change just depend on the temperature as it is an ideal gas, therefore, since the process es isothermic:

\Delta h=Cp\Delta T=0

Best regards.

3 0
4 years ago
At 6pm, you see logs piled up for a campfire. Later you see flames and feel heat from it. At 8pm, only smoldering ashes remain.
mr_godi [17]

The process that took place is called oxidation or burning where wood was burnt into ashes.

<h3><u>Explanation:</u></h3>

Wood is an organic compound formed of different types of carbohydrates, proteins and lipids. These components do have carbon oxygen hydrogen as most abundant atoms and also has some amount of nitrogen, phosphorous, and other metal ions like magnesium, calcium etc.

When the logs were burnt, the chemical reaction took place between the atmospheric oxygen and the atoms present in the wood, forming different oxides. As carbon was the most abundant atom present, a huge smoke containing carbon dioxide and carbon monoxide evolved. The hydrogen became the water vapour, and other gases were also formed like nitrogen dioxide, sulphur dioxide etc. These gases went off into atmosphere. The rest that were left behind were mixture of unburnt part of wood as well as the solid metal oxides. There were unburnt particles of carbon mixed with them too.

8 0
4 years ago
Consider the reaction below. Mg(s) + 2HCl(aq) mc019-1.jpg H2(g) + MgCl2(aq) What is the most likely effect of an increase in pre
bonufazy [111]
1) Reaction:

Mg(s) + 2HCl (aq) ----> H2(g) + MgCl2(aq)

2) Analysis

An increase in pressure affects directly the rate of reaction involving reactiong gases. Changing the pressure where there are only solids or liquids does not affect the rate of reaction.

This reaction is not an equilibrium, the reaction is only forward. So, the reacting components, Mg(s) and HCl(aq) are a solid and a liquid.

Therefore, the reaction is not affected by the change in pressure.

Answer: the reaction is not affected at all.


4 0
3 years ago
Read 2 more answers
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