Answer:
The new temperature will be 565.83 K.
Explanation:
Gay Lussac's law establishes the relationship between the temperature and the pressure of a gas when the volume is constant. This law says that the pressure of the gas is directly proportional to its temperature. This means that if the temperature increases, the pressure will increase; or if the temperature decreases, the pressure will decrease.
In other words, Gay-Lussac's law states that when a gas undergoes a constant volume transformation, the ratio of the pressure exerted by the gas temperature remains constant:
When an ideal gas goes from a state 1 to a state 2, it is true:
In this case:
- P1= 180 kPa
- T1= 291 K
- P2= 350 kPa
- T2= ?
Replacing:
Solving:
T2= 565.83 K
<u><em>The new temperature will be 565.83 K.</em></u>
Answer: If an object has more protons than electrons, then the net charge on the object is positive. If there are more electrons than protons, then the net charge on the object is negative. If there are equal numbers of protons and electrons, then the object is electrically neutral.
Explanation:
Answer:
Explanation:
Hello!
In this case, when performing mathematical operations with numbers in scientific notation, the first step is to write them in standard notation:
550 - 65.0
Thus, the result without any significant figures-based analysis is:
615.0
However, since 550 is significant to the ones and 65.0 to the tenths, we need to round the result to the bigger significance, in this case to the ones; therefore the appropriate result would be:
615
That in scientific notation would be:
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C. Weak acids partially ionize
Answer:
c. H2(g) + CuO(s) → Cu(s) + H2O(l)
e. H2(g) + Cl2(g) → 2HCl(g)
Explanation:
A redox reaction is a reaction that involves a changes in oxidation number of the species involved in the reaction.
The oxidizing agent experiences a decrease in oxidation number while the reducing agent experiences an increase in oxidation number.
For H2(g) + CuO(s) → Cu(s) + H2O(l)
Copper is reduced from +2 to 0 while hydrogen is oxidized from 0 to +2 Hence hydrogen is the reducing agent while copper is the oxidizing agent.
For H2(g) + Cl2(g) → 2HCl(g)
Chlorine is reduced from 0 to -1 while hydrogen is oxidized from 0 to +1. Hence chlorine is the oxidizing agent while hydrogen is the reducing agent.
