If ti takes 50 seconds to lift 10 newtons of books to a height of 7 meters, calculate the power required.

A Ferris wheel has a diameter of 60 m and a period of rotation of 70 s. A passenger weighs 500 N. What is her apparent weight at

andrew11 [14]

Answer:

A

Explanation:

Hopefully this helps.

8 0

3 years ago

Please answer the number 5 6 and 7. I don't know what to do its our hw in physics. (new lesson as well)

Aleks04 [339]

From the picture, I see that you had no trouble at all with #4.
Well, #5, 6, and 7 are easily handled in exactly the same way.

Just as you did with #4, please sketch these on paper
as I walk you through the solutions. That'll help you see
immediately what's going on.

#5.b).
Traveling east at 3 m/s for 4 seconds,
he covers (3 m/s) x (4 sec) = 12 meters.

Traveling south at 5 m/s for 2 seconds,
he covers (5 m/s) x (2 sec) = 10 meters.

The total distance he covers is (12m + 10m) = 22 meters.

#5.c).
Average speed (scalar)

   = (distance covered)/(time to cover the distance)

   = (22 meters)/(6 sec) = 3-2/3 m/s .

#5.d).
Displacement (vector)

   = distance between the start-point and the end-point,
regardless of the route traveled,

in the direction from the start-point to the end-point.

Distance from the start-point to the end-point =

   √(12² + 10²) = √(144 + 100) = √(244) = 15.62 meters

in the direction of arctan(10/12) south of east

   = 39.8° south of east.

#5.e).
Average velocity (vector) =

   (displacement vector) / (time)

   = 15.62 meters directed 39.8° south of east / 6 seconds

   = 2.603 m/s directed 39.8° south of east.

#6).
Magnitude = √(5.2² + 2.1²) = √(27.04 + 4.41) = √31.45 = 5.608 km.

Direction = arctan(5.2/2.1) south of east

= 68° south of east = 158° bearing .

#7).
Magnitude = √(39² + 57²) = √(1521 + 3249) = √( 4770)

   = 69.07 m/s .

Direction = arctan (57/39) south of west

   = 55.6° south of west

Bearing = 214.4°

Compass: 0.65° past "southwest by south".

I'm grateful for the privilege and opportunity to practice my math,
and I shall cherish the bounty of 5 points that came with it.

8 0

3 years ago

Which two charges of a magnet will attract?

ale4655 [162]

Answer:

The other end is called the south pole. When two magnets are brought together, the opposite poles will attract one another, but the like poles will repel one another. This is similar to electric charges.

Explanation:

4 0

2 years ago

Read 2 more answers

The wheel on an upside-down bicycle moves through 18.0 rad in 5.39 s. What is the wheel’s angular acceleration if its initial an

Elden [556K]

Explanation:

Formula to calculate angular acceleration is as follows.

$\Delta (\theta) = \frac{1}{2} \alpha \Delta t^{2} + \omega_{1} \Delta t$

or, $\alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}$

Putting the given values into the above formula as follows.

$\alpha = \frac{2(\Delta (\theta) - \omega_{1} \Delta t)}{\Delta t^{2}}$

= $\frac{2(18.0 rad - 2.5 rad/s \times 5.30 s)}{(5.39)^{2}}$

= 0.326 $rad/s^{2}$

Thus, we can conclude that the wheel’s angular acceleration if its initial angular speed is 2.5 rad/s is 0.326 $rad/s^{2}$ .

5 0

3 years ago

Suppose a car travels 108 km at a speed of 30.0 m/s, and uses 1.90 gallons of gasoline. Only 30% of the gasoline goes into usefu

Aleksandr [31]

Answer:

686.11 N

1.7733 gallons

Explanation:

$\eta$ = Efficiency = 30%

V = Volume of gasoline

E = Energy content of gasoline = $1.3\times 10^8\ J/gal$

F = Force

s = Displacement = 108000 m

v = Velocity

Work done is given by

$W=F\times s\\\Rightarrow F=\frac{W}{s}\\\Rightarrow F=\frac{VE\eta}{s}\\\Rightarrow F=\frac{1.9\times 0.3\times 1.3\times 10^8}{108000}\\\Rightarrow F=686.11\ N$

The force required to keep the car moving at a constant speed is 686.11 N

Here the force is directly proportional to speed

$\\\Rightarrow F=v$

$\\\Rightarrow \frac{F_1}{v_1}=\frac{F_2}{v_2}\\\Rightarrow F_2=\frac{F_1\times v_2}{v_1}\\\Rightarrow F_2=\frac{686.11\times 28}{30}\\\Rightarrow F_2=640.36\ N$

$W=F\times s\\\Rightarrow 0.3\times 1.3\times 10^8\times V=640.36\times 108000\\\Rightarrow V=\frac{640.36\times 108000}{0.3\times 1.3\times 10^8}\\\Rightarrow V=1.7733\ gal$

The gallons that will be used is 1.7733 gallons

7 0

3 years ago