Suppose, you are cleaning your reading table and keeping your books one upon another. Your

You are NASA. Build a space station on Mars that could support humans to live in for an extended period of time.

Ierofanga [76]

Literally just do the project

3 0

3 years ago

Saturated liquid-vapor mixture of water, called wet steam, in a steam line at 1500 kPa is throttled to 50 kPa and 100°C. What is

frozen [14]

Answer:

$x = 0.944$

Explanation:

Steam at outlet is an superheated steam, since $T > T_{sat}$ . From steam tables, the specific enthalpy is:

$h_{out}=2682.4\,\frac{kJ}{kg}$

The throttle valve is modelled after the First Law of Thermodynamics:

$h_{in} = h_{out}$

Hence, specific enthalpy at inlet is:

$h_{in}=2682.4\,\frac{kJ}{kg}$

The quality in the steam line is:

$x = \frac{2682.4\,\frac{kJ}{kg}-844.55\,\frac{kJ}{kg}}{2791.0\,\frac{kJ}{kg} - 844.55\,\frac{kJ}{kg} }$

$x = 0.944$

6 0

3 years ago

Calculate the unit cell edge length for an 80 wt% Ag−20 wt% Pd alloy. All of the palladium is in solid solution, the crystal str

alisha [4.7K]

Answer:

λ^3 = 4.37

Explanation:

first let us to calculate the average density of the alloy

for simplicity of calculation assume a 100g alloy

80g --> Ag

20g --> Pd

ρ_avg= 100/(20/ρ_Pd+80/ρ_avg)

= 100*10^-3/(20/11.9*10^6+80/10.44*10^6)

= 10744.62 kg/m^3

now Ag forms FCC and Pd is the impurity in one unit cell there is 4 atoms of Ag since Pd is the impurity we can not how many atom of Pd in one unit cell let us calculate

total no of unit cell in 100g of allow = 80 g/4*107.87*1.66*10^-27

= 1.12*10^23 unit cells

mass of Pd in 1 unit cell = 20/1.12*10^23

Now,

ρ_avg= mass of unit cell/volume of unit cell

ρ_avg= (4*107.87*1.66*10^-27+20/1.12*10^23)/λ^3

λ^3 = 4.37

6 0

3 years ago

Whats the boolean expression of this circuit?

Natalija [7]

Answer:

G8 = x0'x2' +x0'x3' +x1x2

Explanation:

The expression can be written different ways, depending on the need to avoid hazards. One of them is ...

$G_8=\overline{X_0}\,\overline{X_2}+\overline{X_0}\,\overline{X_3}+X_1X_2$

__

A truth table and Karnaugh map are shown for the circuit. The terms used in the Boolean expression come from the corners, the upper half of the left- and right-columns, and the right half of the middle two rows. If a static hazard is to be avoided, a term x1x0' could be added representing the right column.

8 0

2 years ago

(a) The reverse-saturation current of a pn junction diode is IS = 10−11 A. Determine the diode voltage to produce currents of (i

kirill115 [55]

Answer:

The equation used to solve a diode is

$i_d = I_se^\frac{V_d}{V_T}-1$

$i_d$ is the current going through the diode
$I_s$ is your saturation current
$V_D$ is the voltage across your diode
$V_T$ is the voltage of the diode at a certain room temperature. by default, you always use $V_T=25.9mV$ for room temperature.

If you look at the equation, $i_d = I_se^\frac{V_d}{V_T}-1$ , you'd notice that the $e^\frac{V_d}{V_T}$ grow exponentially fast, so we can ignore the -1 in the equation because it's so small compared to the exponential.