Which statment best describes the chamces that occured in the reactant in forming the alkene product
1 answer:
Hello. You did not enter answer options. The options are:
a. The OH group was removed from the reactante
b. The OH group was replaced by an H atom.
c. Two atoms were removed from the reactant.
d. An H atom abd a OH group have been removed drom the reactant.
In addition, you forgot to add an image that complements the question. The image is attached below.
Answer:
d. An H atom abd a OH group have been removed drom the reactant
Explanation:
As you can see in the image, the reagent is an alcohol molecule. For the transformation of the alcohol molecule into an alkene molecule, it is necessary that an intramolecular dehydration occurs, that is, it is necessary that a water molecule (two H atoms and an O atom) go out from inside the alcohol and that is exactly what happened, that is, we can say that an H atom and an OH group were removed from the reagent to form the alkene.
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This is an incomplete question, here is a complete question and an image is attached below.
The following diagrams represent mixtures of NO(g) and O₂(g). These two substances react as follows:
It has been determined experimentally that the rate is second order in NO and first order in O₂.
Based on this fact, which of the following mixtures will have the fastest initial rate?
The mixture (1). The mixture (2). The mixture (3).
Answer : The mixture 1 has the fastest initial rate.
Explanation :
The given chemical reaction is:
The rate law expression is:
Now we have to determine the number of molecules of
In mixture 1 : There are 5 and 4
molecules.
In mixture 2 : There are 7 and 2
molecules.
In mixture 3 : There are 3 and 5
molecules.
Now we have to determine the rate law expression for mixture 1, 2 and 3.
The rate law expression for mixture 1 is:
The rate law expression for mixture 2 is:
The rate law expression for mixture 3 is:
Hence, the mixture 1 has the fastest initial rate.
