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abruzzese [7]
2 years ago
6

A 125g sample of a mixture of salt and sand contains 12% salt.

Chemistry
1 answer:
natka813 [3]2 years ago
4 0
12 % salt is present in 125 g mixture of salt and sand.
Keep in mind that the total percentage is always 100 %
Therefore, if 12 % is the salt, remaining 88 % must be
sand.
a. The amount of mixture is 125 q. Here, 12 % of 125 is
12 * 125 / 100 = 15 g of salt is present in 125 g mixture.
b. The amount of sand can be calculated similarly, 88 %
of 125 g is 88 * 125 / 100 = 110 g of sand is present in
125 g mixture.
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Calculate the number of grams of sodium chloride in the solution. (Hint: Remember that sodium chloride is a strong electrolyte.)
creativ13 [48]

The question is incomplete, here is the complete question:

A solution contains 0.115 mol  H_2O and an unknown number of moles of sodium chloride. The vapor pressure of the solution at  30°C  is 25.7 torr. The vapor pressure of pure water at this temperature is 31.8 torr. Calculate the number of grams of sodium chloride in the solution. (Hint: Remember that sodium chloride is a strong electrolyte.)

<u>Answer:</u> The mass of sodium chloride in the solution is 0.714 grams

<u>Explanation:</u>

The formula for relative lowering of vapor pressure will be:

\frac{p^o-p_s}{p^o}=i\times \chi_{\text{solute}}

where,  

p^o = vapor pressure of solvent (water) = 31.8 torr

p^s = vapor pressure of the solution = 25.7 torr

i = Van't Hoff factor = 2

\chi_{\text{solute}} = mole fraction of solute (sodium chloride) = ?

Putting values in above equation, we get:

\frac{31.8-25.7}{31.8}=2\times \chi_{NaCl}\\\\\chi_{NaCl}=0.0959

Mole fraction of a substance is calculated by using the equation:

\chi_A=\frac{n_A}{n_A+n_B}

\chi_{\text{NaCl}}=\frac{n_{\text{NaCl}}}{n_{\text{NaCl}}+n_{\text{water}}}

We are given:

Moles of water = 0.115 moles

0.0959=\frac{n_{\text{NaCl}}}{n_{\text{NaCl}}+0.115}\\\\n_{\text{NaCl}}=0.0122mol

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of NaCl = 0.0122 moles

Molar mass of NaCl = 58.5 g/mol

Putting values in above equation, we get:

0.0122mol=\frac{\text{Mass of NaCl}}{58.5g/mol}\\\\\text{Mass of NaCl}(0.0122mol\times 58.5g/mol)=0.714g

Hence, the mass of sodium chloride in the solution is 0.714 grams

5 0
3 years ago
Which coefficients will balance the following reaction:
valentina_108 [34]

Answer:

C ) 2, 1, 2

Explanation:

The given reaction is synthesis reaction in which lithium and bromine react to form lithium bromide.

Chemical equation:

Li + Br₂    →    LiBr

Balanced chemical equation:

2Li + Br₂    →    2LiBr

Step 1:

Li + Br₂    →    LiBr

left hand side                         Right hand side

Li = 1                                        Li = 1

Br = 2                                        Br = 1

Step 2:

Li + Br₂    →    2LiBr

left hand side                         Right hand side

Li = 1                                        Li = 2

Br = 2                                        Br = 2

Step 3:

2Li + Br₂    →    2LiBr

left hand side                         Right hand side

Li = 2                                       Li = 2

Br = 2                                        Br = 2

3 0
3 years ago
What happens to the chemical identity of a substance during a physical change?
klio [65]
Nothing happens because a physical change only changes the appearance of the substance, whereas a chemical change transforms the substance into something completely different.
i.e. (chemical change) wood + fire = ash
(physical change) wood + axe = smaller pieces of wood
5 0
3 years ago
Why is cell uncountable? ​
disa [49]

Answer:

Cells are uncountable becasue they move around your body, make up your skin and other organs as well. And because when you grow, the cells multiply, and that makes it very hard for scientists to count cells in a human's body.

Explanation:

Hope this helped!

3 0
3 years ago
In the following equation, which element has been reduced?
Mila [183]
The answer is A. you sre correct!
4 0
2 years ago
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