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salantis [7]
2 years ago
11

What type of elements are found in each group?

Chemistry
2 answers:
77julia77 [94]2 years ago
8 0

Answer:

Groups are numbered 1–18 from left to right. The elements in group 1 are known as the alkali metals; those in group 2 are the alkaline earth metals; those in 15 are the pnictogens; those in 16 are the chalcogens; those in 17 are the halogens; and those in 18 are the noble gases.

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devlian [24]2 years ago
4 0

Group 1 of the periodic table consists of hydrogen and the alkali metals. ...

Group 2 consists of the alkaline Earth metals. ...

Groups 3–12 contain transition metals. ...

Groups 13–16 each contain at least one metalloid. ...

Group 17 contains halogens. ...

Group 18 consists of noble gases.

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Answer:

60.1 i think

Explanation:

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3 years ago
The atomic mass of an element is 32.07 u and its atomic number is 16. The number of protons contained in the nucleus of an atom
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I THINK IT IS 16 BECAUSE THE ATOMIC NUMBER AND THE NUMBER OF PROTONS ARE THE SAME
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The thin outer layer of Earth, called the crust, contains only 0.50 percent of Earth's total mass and yet is the source of almos
Rzqust [24]

Answer:

The mass of silicon in kilograms in Earth's crust is7.2729\times 10^{21} kg.

Explanation:

Mass of Earth =5.9\times 10^{21} tons

(1 ton= 2000 lb)

(1 lb =453.6 g)

1 ton = 2000 × 453.6 g =907,200 g

Mass of Earth =5.9\times 10^{21}\times 907,200 g=5.3524\times 10^{27} g

Percentage of earth crust = 0.50%

Mass of earth crust = M

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Percentage of the silicon in Earth's crust = 27.2 %

Mass of silicon in in Earth's crust = m

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The mass of silicon in kilograms in Earth's crust is7.2729\times 10^{21} kg.

7 0
3 years ago
A combustion analysis of 5.214 g of a compound yields 5.34 g co 2 ​ , 1.09 g h 2 ​ o, and 1.70 g n 2 ​ . if the molar mass of th
nekit [7.7K]
Answer is: C₃H₃N₃O₃.
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m(H₂) = 1,09 g.
m(N₂) = 1,70 g.
n(CO₂) = n(C) =  5,34 g ÷ 44 g/mol = 0,121 mol.
n(H₂O) = 1,09 g ÷18 g/mol = 0,06 mol.
n(H) = 2 · 0,0605 mol = 0,121 mol.
n(N₂) = 1,7 g ÷ 28 g/mol = 0,0607 mol.
n(N) = 0,0607 mol · 2 = 0,121 mol.
n(C) : n(H) : n(N) = 0,121 mol : 0,121 mol : 0,121 mol /: 0,121
n(C) : n(H) : n(N) = 1 : 1 : 1.
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n(O₂) = 2,914 g ÷ 32 g/mol = 0,09 mol.
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n(CₓHₓNₓOₓ) : n(CO₂) = 1 : 3.


3 0
3 years ago
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Given the incomplete equation representing a reaction:
Akimi4 [234]
O is what should go in the blank. O stands for Oxygen.
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