65 are required to produce 37.15 g CO2
<h3>Answer : </h3>
<h3>→ TRUE </h3>
Explanation:
<h3>Air masses are large volumes of air that</h3><h3> have generally the same temperature and</h3><h3> pressure.</h3>
Answer:
The amount of heat that is absorbed when 3.11 g of water boils at atmospheric pressure is 7.026 kJ.
Explanation:
A molar heat of vaporization of 40.66 kJ / mol means that 40.66 kJ of heat needs to be supplied to boil 1 mol of water at its normal boiling point.
To know the amount of heat that is absorbed when 3.11 g of water boils at atmospheric pressure, the number of moles represented by 3.11 g of water is necessary. Being:
the molar mass of water is:
H₂O= 2* 1 g/mole + 16 g/mole= 18 g/mole
So: if 18 grams of water are contained in 1 mole, 3.11 grams of water in how many moles are present?

moles of water= 0.1728
Finally, the following rule of three can be applied: if to boil 1 mole of water at its boiling point it is necessary to supply 40.66 kJ of heat, to boil 0.1728 moles of water, how much heat is necessary to supply?

heat= 7.026 kJ
<u><em>The amount of heat that is absorbed when 3.11 g of water boils at atmospheric pressure is 7.026 kJ.</em></u>
Answer:
There is 3 sulfur and 12 oxygen atoms
Answer:
x=2 (
Explanation:
Mass of
is the mass of remaining sample, because it is a product of loss of drying from initial sample. This means that the mass of water is the mass has been lost.
after fing the masses of
and water you must to find the amount of moles in both cases.



Now you must to find the ratio between both molecules:

So the water is two times copper(II) chloride. (