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2 years ago

Calculate the magnitude of the effort in the given

Physics

1 answer:

Otrada [13]2 years ago

8 0

Moment = Force x Distance from pívot
500x0.5=2.5 x effort
250= 2.5 x effort
effort = 250/2.5= 100N

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What could be a possible explanation why tectonic plates do not all move in the same direction

sweet [91]

Answer:

because the lava underneath the plate was moving in different directions leading to the separation of pangea

Explanation:

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3 years ago

What do deltas and natural levees have in common?

Tpy6a [65]

They are both formed by deposited river sediment.

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3 years ago

You carry a fire hose up a ladder to a height of 10 m above ground level and aim the nozzle at a burning roof that is 9 m high.

schepotkina [342]

Answer:

The value is $P_1 = 314645 \ Pa$

Explanation:

From the question we are told that

The height is $h_2 = 10 m$

The height of the burning roof is $k = 9 m$

The horizontal distance is $d = 7 \ m$

The height of the truck is $h_1 = 0.5 \ m$

Generally the time for the water to hit the roof from the hose is mathematically represented as

$t = \sqrt{\frac{2 * (h_2 - k)}{g} }$

=> $t = \sqrt{\frac{2 * (10 - 9)}{9.8} }$

=> $t = 0.4518 \ s$

Generally the velocity of the water is mathematically evaluated as

$v_2 = \frac{d}{t}$

$v_2 = \frac{ 7}{0.4518}$

$v_2 = 15.5 \ m/s$

Generally from Bernoulli's Equation we have that

$P_1 + \frac{1}{2} v_1^2 * \rho + \rho *g *h_1 = P_2 + \frac{1}{2} v_2^2 * \rho + \rho *g *h_2$

Here $P_1 [\tex] is pressure in the chamber which we are to calculate , [tex]P_2 [\tex] is the atmospheric pressure with value [tex]P_2 = 101325 \ Pa [\tex] , [tex]v_1 [\tex] is the velocity of the water before it starts flowing with value [tex]v_1 = 0 m/s [\tex] , [tex]\rho [\tex] is the density of water with value [tex]\rho = 1000 \ kg/m^3 [\tex] So [tex]P_1 + \frac{1}{2} 0^2 * 1000 + 1000 *9.81 *0.5 = 101325 + \frac{1}{2}* 15.5^2* 1000 + 1000 *9.81 *10$

$P_1 = 314645 \ Pa$

8 0

3 years ago

Part AIf the potential of plate 1 is V, then, in equilibrium, what are the potentials of plates 3 and 6? Assume that the negativ

Nana76 [90]

Answer:

Part a: The potential at point 3 and point 6 are V and 0 respectively.

Part b: The charges Q1, Q2 and Q3 are CV, 2CV and 3CV respectively.

Part c: The net charge is 6CV.

Part d: The equivalent capacitance is 6C

Explanation:

As the question is not given here ,the complete question is found online and is attached herewith.

Part a:

V1 = V, V3 = V1 = V

and, V6 = V1-V = 0

The potential at point 3 and point 6 are V and 0 respectively

Part b

Q1 =CV = Q,

Q2 = 2C *V = 2Q

Q3 = 3 C*V = 3Q

So the charges Q1, Q2 and Q3 are CV, 2CV and 3CV respectively.

Part c

Total charge of the system,

Q_net =Q1+Q2+Q3= (1+2+3) CV = 6 CV

So the net charge is 6CV.

Part d:

Equivalent Capacitance = Net charge / Voltage

Eq. C = 6CV/V = 6C

So the equivalent capacitance is 6C

6 0

3 years ago

How do you work out Potential Difference??? <br> Please can you make it simple :) <br> Thanks.

patriot [66]

Answer:

Potential difference is the work done in moving a positive test charge from infinity to the point in question.

Voltage is an expression of PD. (Joules / Coulomb)

Say that a capacitor has a PD of 5 Volts. The work in moving a positive test charge from the positive plate to the negative plate is -5 Joules/Coulomb or -5 volt. (At the positive plate the positive test charge (1 Coulomb) already has a PD of + 5 Volts.)

7 0

3 years ago

Calculate the magnitude of the effort in the given​

Calculate the magnitude of the effort in the given