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Jobisdone [24]
3 years ago
8

The answer is C, method?

Physics
1 answer:
Arturiano [62]3 years ago
4 0

Answer:

Numbers with more number

Explanation:

am I right or am I right?

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Ubes have sides of equal lengths. What is the fastest way to measure the volume of a cube-shaped table?
Kryger [21]

The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three. Option B is correct.

<h3 /><h3>How do you calculate the volume of a cube?</h3>

Assume the side length of the cube under consideration is L units. The volume of the cube is then equal to L³ cubic units.

The volume of a cube is;

V = L³

Ubes have equal-length sides. The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three.

Hence option B is correct.

To learn more about the volume of a cube refer

brainly.com/question/26136041

#SPJ1

7 0
2 years ago
1. A mass is on a level plane, it has a weight of 20N. What is the coefficient of kinetic friction if an applied force
Arturiano [62]

Answer:

0.4

Explanation:

F-Fr=ma where F is applied force, Fr is friction, m is mass and a is acceleration.

Since the mass is moving with a constant velocity, there's no acceleration hence

F=Fr=\mu N where N is the weight of object and \mu is coefficient of kinetic friction.

F=\mu N and making [tex]\mu the subject

\mu=\frac {F}{N}

Substituting F for 8 N and N for 20 N

\mu=\frac {8}{20}=0.4

Therefore, coefficient of kinetic friction is 0.4

4 0
4 years ago
A motorboat accelerates uniformly from a velocity of 6.5m/s to the west to a velocity of 1.5m/s to the west. if its accelerate w
grigory [225]
A motorboat accelerates uniformly from a velocity of 6.5m/s to the west to a velocity of 1.5m/s to the west. if its accelerate was 2.7m/s2 to the east , how far did it travel during the accelration? Give your answer in units of kilometers per hour/sec. To find the acceleration of the car we have to <span>
1.   First determine the suitable formula for this word problem.
Which is a.   A=vf-vi/t</span> which will be  
Given are: Vi= 6.5 m/s Vf= 1.5 m/s a= 2.7 m/sec2 t=1.85s 
 Solution: <span>
x = v0t + ½at2</span>
<span>x = <span>16.645375 m </span></span>    



7 0
3 years ago
The magnitude of the tidal force between the International Space Station (ISS) and a nearby astronaut on a spacewalk is approxim
vovikov84 [41]

Answer:

F = 4.47 10⁻⁶ N

Explanation:

The expression they give for the strength of the tide is

      F = 2 G m M a / r³

Where G has a value of 6.67 10⁻¹¹ N m² / kg² and M which is the mass of the Earth is worth 5.98 10²⁴ kg

They ask us to perform the calculation

      F = 2 6.67 10⁻¹¹ 135  5.98 10²⁴ 13 / (6.79 10⁶)³

      F = 4.47 10⁻⁶ N

This force is directed in the single line at the astronaut's mass centers and the space station

4 0
3 years ago
Which is a characteristic of the atom marked A
erastovalidia [21]
Its very dense. Hey, are you homeschooled?
6 0
3 years ago
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