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BabaBlast [244]
2 years ago
8

The city council of a small town wanted to add fluoride to their water so that all the residents would have healthier teeth. The

mayor had read that ionic compounds must be used to get the fluoride into water. He looked up fluorine-containing compounds and came up with the following list. ​
NaF NF3 SiF4 CaF2 NH4F​
​
Using academic vocabulary in paragraph form, discuss the following: ​
​
Explain which compound(s) could produce fluoride ions in the water. In your response, be sure to include: ​
° which of the listed compounds are ionic and which are covalent. ​
° how ionic and covalent compounds are different. ​
° why only ionic compounds would produce fluoride in water.​
Chemistry
1 answer:
azamat2 years ago
3 0

Answer:NaF is ionic. NF3 is covalent. SiF4 is ionic. CaF2 is Ionic and  NH4F is also ionic. Ionic compounds transfer electrons whereas covalent compounds share electrons hence the word "co". Also, ionic compounds are formed with metal and nonmetal. Where a covalent is with 2 nonmetals. Only ionic compounds would produce fluoride in water because ionic compounds can dissolve in water and covalent compounds cant.

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As the thermal energy of matter increases, its particles usually spread out, causing
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Answer:

As the thermal energy of matter increases, its particles usually spread out, causing the substance to expand.

Explanation:

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2 years ago
A book is pushed off the edge of a table. At what point during the fall will the potential and kinetic energy be equal?
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Answer:

KE = PE at half the table Height:

Explanation

AT ANY POINT IN THE BOOK'S FALL,

TOTAL E = PE +KE

THE TOTAL E IS CONSTANT

Before the book is pushed off, the total energy is potential

TOT E=PE =MGH

BEFORE THE BOOK HITS THE GROUND, THE TOTAL E IS KINETIC

TOT=KE = MVXV/2

WHEN KE = PE

KE+PE =<u> MGH (STARTING ENERGY SINCE E IS CONSERVED)</u>

<u>OR PE+ PE = MGH</u>

<u>OR MGH' + MGH' =MGH</u>

<u>OR 2H' =</u>H

H' (NEW HEIGHT) =H/2

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2 years ago
PLZ ANSWER FIRST ONE TO ANSWER GETS BRAINLIEST!!!!!!
Roman55 [17]
The answer is “Heat Conduction”
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3 years ago
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A 0.944 M solution of glucose, C6H12O6, in water has a density of 1.0624 g/mL at 20∘C. What is the concentration of this solutio
____ [38]

Answer:

Mole fraction: 0,0157.

Molality: 0,889m

Mass%: 16%

Explanation:

<em>The units are mole fraction, molality and mass%</em>

<em />

Units of mole fraction are moles of glucose per total moles.

Moles of glucose assuming 1L are:

0,944 moles.

Moles of water in 1L are:

1L × (1,0624kg/L) × (1000g / 1kg) × (1mol / 18,02g) = <em>59,0 moles of water</em>

<em />

Mole fraction is: 0,944 moles / (59,0 mol + 0,944mol) = <em>0,0157</em>

Molality is mole of solute (0,944) per kg of solution (1,0624kg):

0,944mol / 1,0624kg = <em>0,889m</em>

<em></em>

In mass percent total mass is 1062,4g and mass of 0,944 moles of glucose is:

0,944mol×(180,156g/1mol) = 170g of glucose. Mass%:

170g / 1062,4g ×100 = <em>16%</em>

<em></em>

I hope it helps!

6 0
2 years ago
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