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vfiekz [6]
2 years ago
12

To qualify to run in the 2005 boston marathon, a distance of 26.2 miles, an 18-year-old woman had to have completed another mara

thon in 3 hours and 40 minutes or less. to qualify, what must a woman's average speed have been in miles per hour?
Physics
2 answers:
Kisachek [45]2 years ago
7 0

Answer:

The woman's average speed must have been 7.14miles/hour. This is the ratio of the total distance she covered/traveled to the total time it took her to cover that distance.

Explanation:

Here is the calculation,

Total distance = 26.2miles

Total time = 3hours and 40min.

40min = (40min/60min) × 1hour = 0.67hour. This is basically converting time in mins to time in hours.

Therefore total time taken = 3hours and 40mins = 3 hours + 0.67 hours = 3.67hours

Average speed = Total distance/Total time taken

Average speed = 26.2miles/3.67 hours = 7.14 miles/hour

oksian1 [2.3K]2 years ago
5 0
3 hours and 40 minutes is equivalent to 3.667 hours. If a woman must have run another marathon (of 26.2 miles) within that time, then her minimum average speed in mph can be calculated by dividing the distance by time:
26.2 miles / 3.667 hours = 7.145 miles per hour
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2 years ago
A 1980-kg car is traveling with a speed of 15.5 m/s. What is the magnitude of the horizontal net force that is required to bring
Dennis_Churaev [7]

Answer: 6067.5 N

Explanation:

Work = Change in Energy. To start, all of the energy is kinetic energy, so find the total KE using: KE = 1/2(m)(v^2). Plug in 1980 kg for m and 15.5 m/s for v and get KE = 237847.5 J.

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5 0
2 years ago
The weight of an object _____.
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The weight of an object is the force with which it is attracted to earth. The gravity of an object or body of an object is high on earth than at the atmosphere. It has an average of gravitational constant equal to 9.8066 or 9.8 meters per second. In truth, the acceleration of the object depend upon its location, the latitude and altitude, on earth.     

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8 0
3 years ago
Read 2 more answers
A clown balances a small spherical grape at the top of his bald head, which also has the shape of a sphere. After drawing suffic
prisoha [69]
<h2>Answer:</h2>

<em><u>48.189°</u></em>

<h2>Explanation:</h2>

Let us say,

Radius of curvature of the clown's bald head is = R

Angle where the grape leaves the contact with the head is (with vertical) = θ

Height from the top of the head at which the contact is lost = y

Mass of the grape = m

Velocity of the grape at the point where it loses contact = v

So,

Using the <u>Conservation of Work and Energy,</u> we can say that there is 0 Work done on the system,

W = ΔK + ΔU

So,

0=(\frac{1}{2}mv^{2}-0)+(mgy-0)\\v^{2}=2gy\\Now,\\y=R-Rcos\theta\\y=R(1-cos\theta)\\So,\\v^{2}=2[R(1-cos\theta)]g

Now, using this at the point where contact is lost,

N=-m(\frac{v^{2}}{R})+mg.cos\theta\\N=-m[2g(1-cos\theta)]+mg.cos\theta\\

At that point the <u>Normal force will be zero, because the contact is lost.</u>

So,

On putting, N = 0 we get,

N=-m[2g(1-cos\theta)]+mg.cos\theta\\0=-m[2g(1-cos\theta)]+mg.cos\theta\\2g-2g.cos\theta=g.cos\theta\\3g.cos\theta=2g\\cos\theta=\frac{2}{3}\\\theta=48.189\,degrees

<em><u>Therefore, the angle at which the grape lose contact with the bald head is at 48.189° from vertical.</u></em>

7 0
2 years ago
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