Explanation:
The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear. These bones are called the malleus, incus, and stapes.
Answer: 6067.5 N
Explanation:
Work = Change in Energy. To start, all of the energy is kinetic energy, so find the total KE using: KE = 1/2(m)(v^2). Plug in 1980 kg for m and 15.5 m/s for v and get KE = 237847.5 J.
Now, plug this in for work: Work = Force * Distance; so, divide work by distance to get 6067.5 N.
The weight of an object is the
force with which it is attracted to earth. The gravity of an object or body of
an object is high on earth than at the atmosphere. It has an average of
gravitational constant equal to 9.8066 or 9.8 meters per second. In truth, the acceleration
of the object depend upon its location, the latitude and altitude, on
earth.
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<h2>
Answer:</h2>
<em><u>48.189°</u></em>
<h2>
Explanation:</h2>
Let us say,
Radius of curvature of the clown's bald head is = R
Angle where the grape leaves the contact with the head is (with vertical) = θ
Height from the top of the head at which the contact is lost = y
Mass of the grape = m
Velocity of the grape at the point where it loses contact = v
So,
Using the <u>Conservation of Work and Energy,</u> we can say that there is 0 Work done on the system,
W = ΔK + ΔU
So,
![0=(\frac{1}{2}mv^{2}-0)+(mgy-0)\\v^{2}=2gy\\Now,\\y=R-Rcos\theta\\y=R(1-cos\theta)\\So,\\v^{2}=2[R(1-cos\theta)]g](https://tex.z-dn.net/?f=0%3D%28%5Cfrac%7B1%7D%7B2%7Dmv%5E%7B2%7D-0%29%2B%28mgy-0%29%5C%5Cv%5E%7B2%7D%3D2gy%5C%5CNow%2C%5C%5Cy%3DR-Rcos%5Ctheta%5C%5Cy%3DR%281-cos%5Ctheta%29%5C%5CSo%2C%5C%5Cv%5E%7B2%7D%3D2%5BR%281-cos%5Ctheta%29%5Dg)
Now, using this at the point where contact is lost,
![N=-m(\frac{v^{2}}{R})+mg.cos\theta\\N=-m[2g(1-cos\theta)]+mg.cos\theta\\](https://tex.z-dn.net/?f=N%3D-m%28%5Cfrac%7Bv%5E%7B2%7D%7D%7BR%7D%29%2Bmg.cos%5Ctheta%5C%5CN%3D-m%5B2g%281-cos%5Ctheta%29%5D%2Bmg.cos%5Ctheta%5C%5C)
At that point the <u>Normal force will be zero, because the contact is lost.</u>
So,
On putting, N = 0 we get,
![N=-m[2g(1-cos\theta)]+mg.cos\theta\\0=-m[2g(1-cos\theta)]+mg.cos\theta\\2g-2g.cos\theta=g.cos\theta\\3g.cos\theta=2g\\cos\theta=\frac{2}{3}\\\theta=48.189\,degrees](https://tex.z-dn.net/?f=N%3D-m%5B2g%281-cos%5Ctheta%29%5D%2Bmg.cos%5Ctheta%5C%5C0%3D-m%5B2g%281-cos%5Ctheta%29%5D%2Bmg.cos%5Ctheta%5C%5C2g-2g.cos%5Ctheta%3Dg.cos%5Ctheta%5C%5C3g.cos%5Ctheta%3D2g%5C%5Ccos%5Ctheta%3D%5Cfrac%7B2%7D%7B3%7D%5C%5C%5Ctheta%3D48.189%5C%2Cdegrees)
<em><u>Therefore, the angle at which the grape lose contact with the bald head is at 48.189° from vertical.</u></em>