Answer:
Option B seems to be the appropriate choice,
Explanation:
The given question is incomplete. Please find the attachment of the complete question.
- From either the principle or law of the Coulombs, there would have been either pressure (force) through attachment or repulsion amongst charges.
- It is evident from the analysis presented that perhaps the bee becomes positively (+) charged and would have been drawn either by negatively (-) charged roots of the plants or stem.
As a consequence, the vegetation is electric current polarized because as activated bee pursued.
Answer:
0.75 NC⁻¹
Explanation:
Electric field intensity ( or strength of the electric field ) is the force per a 1 C charge,
So, Force (F) = Electric field intensity(E) × Charge (q)
F = E×q ⇒ q = F/E
= 4.5×10⁻⁴/6×10⁻⁴ = 0.75 NC⁻¹
According to cool om's law electric fields are generated due to charges. When charges are same there is a repulsive force acted on both charges. When charges are opposite there is a attraction force acted on both charges.
According to cool om's law,
F =G×q1×q2 / r²
F = force exerted of two charges
q1 , q2 = charges
r = distance between two charges
And also Electric field intensity is a vector which has a magnitude and direction both. Direction is depending on a charge and the sign of the charge
Answer: 4550 Joules
The formula for potential energy in gravitational field is as follows:
I think it’s Energy is lost when machines don’t work right.
