The period ( measured in s) is the amount of time is takes for the pendulum to make a single cycle, i.e. how long it takes to swing in both direction. The frequency (measured in Hz) is the inverse of the period, the number of cycles it completes in one second.
So long as you know one you can find the other by diving 1 by it. Period = 1 / frequency, and frequency = 1 / period
If the pendulum takes 2s in each direction, then it has a period of 4s. So the frequency = 1 / 4s = 0.25Hz
Answer:
The field strength needed is 0.625 T
Explanation:
Given;
angular frequency, ω = 400 rpm = (2π /60) x (400) = 41.893 rad/s
area of the rectangular coil, A = L x B = 0.0611 x 0.05 = 0.003055 m²
number of tuns of the coil, N = 300 turns
peak emf = 24 V
The peak emf is given by;
emf₀ = NABω
B = (emf₀ ) / (NA ω)
B = (24) / (300 x 0.003055 x 41.893)
B = 0.625 T
Therefore, the field strength needed is 0.625 T
Answer:
222.5 Gpa
Explanation:
From definition of engineering stress, 
where F is applied force and A is original area
Also, engineering strain, 
where l is original area and 
is elongation
We also know that Hooke's law states that 
Since A=20 mm* 20 mm= 0.02 m*0.02 m
F= 89000 N
l= 100 mm= 0.1 m
By substitution we obtain
Answer:
BDEG
Explanation:
got it right on the test on edge because i used my b r a i n
