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Colt1911 [192]
2 years ago
15

PLEASE HELP!!!!!

Physics
1 answer:
ra1l [238]2 years ago
4 0

Answer:

The total annual amount of carbon captured by the world ocean is 0.1 times 83 million

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The Nardo ring is a circular test track for cars. It has a circumference of 12.5 km. Cars travel around the track at a constant
KIM [24]

Answer: 50 km, 0, 27.78 m/s

Explanation:

Given

Circumference of the track is 12.5\ km

Speed of car is 100\ km/h

Car drives for 30\ \text{minute}\ or\ 0.5\ hr

(a)Distance traveled is

\Rightarrow D=100\times 0.5\\\Rightarrow D=50\ km

(b)displacement of the car

It can be observed that 12.5 is a multiple of 50, that is, 50 km can be interpreted as 4 complete rounds of the track.

Therefore, the displacement of the car is zero.

(c)To convert kmph to m/s, multiply the entity by \frac{5}{18}

\Rightarrow 100\times \dfrac{5}{18}\\\\\Rightarrow 27.78\ m/s

5 0
3 years ago
Two oppositely charged objects are separated by a small distance. The objects are then moved three times farther apart from each
stepan [7]
Force is indirectly proportional to the distance. Therefore when the distance increases the force of attraction increases and the answer would be B
7 0
3 years ago
in terms of mechanical advantage and velocity ratio write an expression for the efficiency of a simple machine​
mixer [17]

Answer:

Efficiency = (MA/VR) ×100%

8 0
3 years ago
what polarity must the red tip of the compass needle be since it points toward the south pole of the magnet?
Marrrta [24]

Answer: positive

Explanation: because opposites attract and north=positive and south=negative the answer should be positive.

8 0
3 years ago
A cheetah goes from 0m/s to 25m/s in 2.5 s. What is the cheetah's rate of acceleration?
RUDIKE [14]

Answer:

10 m/s²

Explanation:

Acceleration: This the rate of change of velocity. The unit of acceleration is m/s²

From the question,

a = (v-u)/t.................... Equation 1

Where a = acceleration of the cheetah, v = final velocity of the cheetah, u = initial velocity of the cheetah, t = time.

Given: u = 0 m/s, v = 25 m/s, t = 2.5 s.

Substitute these values into equation 1

a = (25-0)/2.5

a = 25/2.5

a = 10 m/s²

Hence the acceleration of the cheetah = 10 m/s²

6 0
3 years ago
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