The amount of heat needed would be the specific heat multiplied by the mass of the substance and the temperature difference. In this case, the mass would be 75.0–g, the specific heat would be 0.449 j/g °c, and the temperature difference would be <span>1535 -25= 1510
Then the calculation would be: </span>0.449 j/g °c * 75g * 1510°c = 50,849.25J
In calorie it would be: 50849.25J / 4.184J/cal= 12,153.26 calorie
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Answer:</h3>
45°C
<h3>
Explanation:</h3>
We are given;
- Quantity of heat = 1.95 kJ
- Mass of lead = 500 g
- Initial temperature = 15° C
- heat capacity of lead is 130 J/kg°C
We are required to calculate the final temperature;
- We need to know that the quantity of heat is given by the formula;
Q = mass,m × specific heat,c × Change in temperature,ΔT
ΔT = final temperature - initial temperature
We can rearrange the formula to calculate the change in temperature
ΔT = Q ÷ (m×c)
Therefore;
ΔT = 1950 J ÷ (0.5 kg × 130 J/Kg°C)
= 30°C
But,
Final temperature = ΔT + Initial temperature
= 15°C + 30°C
= 45°C
Therefore, the final temperature is 45°C