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diamong [38]
2 years ago
7

Pls help if you only know the correct answer! Thanks!!

Chemistry
1 answer:
Likurg_2 [28]2 years ago
4 0

Answer:

1. H=2, O=1

2. H=4, O=2

3. C=1, O=1

4.

a. reactants C=1, O=2

b. products C=1, O=2

5.

a. reactants H=4, O=2

b. products H=4, O=2

6

a. reactants C=1, O=1, H=4

b. products C=1, O=1, H=4

You might be interested in
How many moles are in 9.50 x 1022 molecules of CO? Be sure to ALL work below and report your answer using the correct number of
eimsori [14]

Answer:

0.158 moles

Explanation:

We are given;

9.50 x 10^22 molecules of CO

We are required to determine the number of moles;

We need to know;

1 mole of a compound = 6.022 × 10^23 molecules

Therefore;

9.50 x 10^22 molecules of CO will be equivalent to;

= 9.50 x 10^22 molecules ÷ 6.022 × 10^23 molecules/mole

= 0.158 moles

Therefore, the number of moles are 0.158 moles

4 0
4 years ago
Can someone help me, please?
VikaD [51]
15. D is correct, exothermic reactions release heat

I am not sure about 16
7 0
3 years ago
Which of the following statements is FALSE?
Alborosie

Answer:

The answer to your question is: letter E

Explanation:

A. This option is correct, the n = 3 shell only has subshells: s, p and d, and shell n = 4 or 5 have f subshell.

B. This option is true in subshell p could be at most 6 electrons and 3 suborbitals.

C. This option is correct orbital "s" is a sphere.

D. This option is correct, in subshell d could be at most 10 electrons and 5 orbitals.

E. This option is false, hydrogen only has 1 electron and then one subshell (s).

6 0
3 years ago
In the reaction C + O2 → CO2, 18 g of carbon react with oxygen to produce 72 g of carbon dioxide. What mass of oxygen would be n
artcher [175]
Stoichiomety:

1 moles of C + 1 mol of O2 = 1 mol of CO2

multiply each # of moles times the atomic molar mass of the compund to find the relation is weights

Atomic or molar weights:

C: 12 g/mol
O2: 2 * 16 g/mol = 32 g/mol
CO2 = 12 g/mol + 2* 16 g/mol = 44 g/mol

Stoichiometry:

12 g of C react with 32 g of O2 to produce 44 g of CO2

Then 18 g of C will react with: 18 * 32/ 12 g of Oxygen = 48 g of Oxygen

And the result will be 12 g of C + 48 g of O2 = 60 g of CO2.

You cannot obtain 72 g of CO2 from 18 g of C.

May be they just pretended that you use the law of consrvation of mass and say that you need 72 g - 18g = 54 g. But it violates the proportion of C and O2 in the CO2 and is not possible.
3 0
4 years ago
Read 2 more answers
What pressure is required to achieve a co2 concentration of 7.90×10−2 m at 20∘c?
Savatey [412]

Answer:-  1.90 atm

Solution:- It is based on combined gas law equation, PV = nRT

In this equation, P is pressure, V is volume, n is moles of gas, R is universal gas constant and T is kelvin temperature.

If we divide both sides by V then:

P=\frac{nRT}{V}

We know that, molarity is moles per liter. So, in the above equation we could replace \frac{n}{V} by molarity, M of the gas. The equation becomes:

P = MRT

T = 20 + 273 = 293 K

M = 7.9*10^-^2

Let's plug in the values in the equation:

P = (7.9*10^-^2)(0.0821)(293)

P = 1.90 atm

So, the pressure of the gas is 1.90 atm.

7 0
4 years ago
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