1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
diamong [38]
2 years ago
7

Pls help if you only know the correct answer! Thanks!!

Chemistry
1 answer:
Likurg_2 [28]2 years ago
4 0

Answer:

1. H=2, O=1

2. H=4, O=2

3. C=1, O=1

4.

a. reactants C=1, O=2

b. products C=1, O=2

5.

a. reactants H=4, O=2

b. products H=4, O=2

6

a. reactants C=1, O=1, H=4

b. products C=1, O=1, H=4

You might be interested in
Mountain-building is a ________ process on Earth.<br> A. destructive<br> B. constructive
serg [7]
I'm pretty sure it's B)constructive
7 0
3 years ago
Read 2 more answers
What is true about all matter?
Ipatiy [6.2K]
Alll are correct. Matter is literally everywhere
8 0
3 years ago
What volume of 0.235 M H2SO4 is needed to titrate 40.0 mL of 0.0500 M Na2CO M NaCO3 solution?
Andreyy89

Answer: The volume of 0.235 M H_2SO_4 needed to titrate 40.0 mL of 0.0500 M Na_2CO_3 is 8.51 ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Na_2CO_3

We are given:

n_1=2\\M_1=0.235M\\V_1=?mL\\n_2=2\\M_2=0.0500M\\V_2=40.0mL

Putting values in above equation, we get:

2\times 0.235\times V_1=2\times 0.0500\times 40.0\\\\V_1=8.51mL

Thus volume of 0.235 M H_2SO_4 needed to titrate 40.0 mL of 0.0500 M Na_2CO_3 is 8.51 ml

5 0
3 years ago
Write a balanced half-reaction describing the oxidation of aqueous vanadium(i) cations to aqueous vanadium(v) cations.
andrew-mc [135]

<span>The balanced half-reaction: V</span>⁺(aq) → V⁵⁺(aq) + 4e⁻.

Vanadium(I) cations lose four electrons and became vanadium(V) cations.

<span> Oxidation reaction is increasing of oxidation number of element, because element or ion lost electrons in chemical reaction.
Reduction is lowering oxidation number because element or ions gain electrons.</span>

8 0
3 years ago
Read 2 more answers
Need help asap Pleases
ioda
B only plants and some prokaryotes have cell walls
8 0
2 years ago
Other questions:
  • What are chemical properties of ionic compounds
    15·1 answer
  • An aspirin tablet contains 325 mg acetylsalicylic acid. How many acetylsalicylic acid molecules does it contain?
    13·1 answer
  • Gold forms face-centered cubic crystals. The atomic radius of a gold atom is 144 pm. Consider the face of a unit cell with the n
    9·1 answer
  • What is the Bohr model of hydrogen​
    11·1 answer
  • WILL MARK BRAINLIST!!! only for correct answer<br> NEED CORRECT ANSWER ASAPPP
    9·1 answer
  • Automobile air bags use the decomposition of sodium azide as their sources of gas for rapid inflation, represented in the reacti
    15·1 answer
  • Balance kclo3-kcl+02​
    6·1 answer
  • One third of the united states carbon consumption is used to operate what
    8·2 answers
  • write the chemical formula of the following compounds sodium sulfate magnesium chloride aluminum nitrate ammonium sulfate​
    12·1 answer
  • Simple distillation experiment lab report
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!