The net force acting on the block is ~
So, the Answer in the boxes will be ~
Quddus and Saadman start running together from the same point. Quddus runs at constant velocity 0.5ms−1. Saadman’s initial veloc
1 answer:
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Answer:
0.3814128 m
Explanation:
t = Time taken = 36 ms
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration = 60g
g = Acceleration due to gravity = 9.81 m/s²
The distance the person traveled is 0.3814128 m
A) 2.64 H
The maximum height that the expelled rock can reach can be found by using the equation:
where
v = 0 is the velocity at the maximum height
u is the initial velocity
g is the acceleration of gravity
d is the maximum height
Solving for d,
We see that the maximum heigth is inversely proportional to g. On the Earth,
and
So we can write:
where H' is the maximum height reached on Mars, and is the acceleration of gravity on Mars. Solving for H',
B) 2.64T
The time after which the rock reaches the maximum height can be found by using
where
v = 0 is the velocity at the maximum height
u is the initial velocity
Solving for t,
The total time of the motion is twice this value, so:
So we see that it is inversely proportional to g.
On the Earth, t = T. So we can write:
where T' is the total time of the motion on Mars. Solving for T',