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Romashka-Z-Leto [24]
3 years ago
10

Gravity, inertia, momentum, kinetic energy and centrifugal force are all _______ forces a driver must deal with.

Physics
2 answers:
Elan Coil [88]3 years ago
8 0

Answer:

Natural Forces

Nikitich [7]3 years ago
4 0

Well gee, you got me there, dude.

Gravity is a force that a driver doesn't much have to worry about. Inertia, momentum, and kinetic energy are not forces, and centrifugal force doesn't exist.

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A flywheel of diameter 1.2 m has a constant angular acceleration of 5.0 rad/s2. the tangential acceleration of a point on its ri
vodka [1.7K]
We know that tangential acceleration is related with radius and angular acceleration according the following equation:  
at = r * aa  
where at is tangential acceleration (in m/s2), r is radius (in m) aa is angular acceleration (in rad/s2)  
So the radius is r = d/2 = 1.2/2 = 0.6 m  
Then at = 0.6 * 5 = 3 m/s2  
Tangential acceleration of a point on the flywheel rim is 3 m/s2
5 0
3 years ago
What is the magnitude of the velocity of a 25 kg mass that is moving with a momentum of 100 kg*m/s?
Gekata [30.6K]

Answer:

v= 4 m/s

Explanation:

Momenutm is, by definition, the product of mass and velocity.

p = mv

Let's replace what we know and solve for whatever's left

100 kg\cdot m/s = 25kg \cdot v \rightarrow v= 4 m/s

7 0
3 years ago
PLEASE HELP ASAP
morpeh [17]
A is the correct answer
7 0
3 years ago
A uniform electric field of magnitude 4.6 ✕ 104 N/C is perpendicular to a square sheet with sides 3.0 m long. What is the electr
rodikova [14]

Answer:

41.4* 10^4 N.m^2/C

Explanation:

given:

E= 4.6 * 10^4 N/C

electric field is 4.6 * 10^4 N/C and square sheet is perpendicular to electric field so, area of vector is parallel to electric field

then electric flux = ∫ E*n dA

                            = ∫ 4.6 * 10^4 * 3*3

                            = 41.4* 10^4 N.m^2/C

3 0
4 years ago
Read 2 more answers
A projectile falls beneath the straight-line path it would follow if there were no gravity. How many meters does it fall below t
maria [59]

Answer:

Explanation:

Suppose v is the initial velocity and \theta is the angle of inclination

distance traveled in vertical direction in t=1 s

When gravity is present

y=vt+\frac{1}{2}at^2

where y=vertical\ distance

a=acceleration

t=time

v=initial\ velocity

here initial velocity is v\sin \theta [/tex] so

y=v\sin \theta \times 1-\frac{1}{2}gt^2

y=v\sin \theta -0.5g

In absence of gravity

y_2=v\sin \theta \times t

y_2=v\sin \theta \times 1

\Delta y=y_2-y=v\sin \theta -v\sin \theta +0.5 g=4.9\ m

         

4 0
3 years ago
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