Question

A 1,800kg rollercoaster is going down a hill with a kinetic energy of 25,000J. What

Answer 1

The velocity of the rollercoaster going down the hill is equal to 5.270 m/s.

Given the following data:

• Mass of rollercoaster = 1,800 kilograms.

• Kinetic energy =25,000 Joules.

To calculate the velocity of the rollercoaster going down the hill:

Formula for kinetic energy.

Mathematically, kinetic energy is calculated by using the formula;

$K.E = \frac{1}{2} MV^2$

Where:

• K.E is the kinetic energy.

• M is the mass of an object.

• V is the velocity of an object.

Making V the subject of formula, we have:

$V =\sqrt{\frac{2K.E}{M} }$

Substituting the given parameters into the formula, we have;

$V =\sqrt{\frac{2\times 25000}{1800} }\\\\V=\sqrt{27.7778}$

Velocity, V = 5.270 m/s

Read more on kinetic energy here: brainly.com/question/17081653