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2 years ago

A rock is released from rest and freely falls 7.0 m to the ground . What is its velocity just before impact?

Physics

2 answers:

mezya [45]2 years ago

7 0

The answer is 9.8 helping is my pleasure

poizon [28]2 years ago

4 0

Answer:

c. 9.8m/s

Explanation:

I answered the same question before on a science test.

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A force of 5 N is applied to the end of a lever that has a length

Klio2033 [76]

Answer:

The answer is 10Nm

Explanation: I ended up just messing around with the numbers, I multiplied 5 and 2 got 10 as my answer and it was right.

4 0

3 years ago

On the basis of which characteristics jute is considerd as a natural fibre

klemol [59]

Answer:

Jute is obtained from Jute plant naturally that is why it is considered as a Natural Fibre. It seems golden in color.

6 0

3 years ago

Is the relationship between the length of a pendulum and its period is valid at all times?

Stels [109]

Yes it is valid all the times under the consideration of acceleration due to gravity .it is not valid on space where there is no influence of gravity

4 0

3 years ago

Please help i'm going to throw up from stress

Eddi Din [679]

Answer:

Explanation:

First of all, I used the specific heat of water as 4182 J/(kgC) and the specific heat of ethyl alcohol (EtOH) as 2440 J/(kgC); that means that we need the masses in kg, not g.

120.g = .1200 kg of ethyl alcohol. Now for the formula:

$t_f=\frac{(m_{H2O}*spheat_{H2O}*temp_{H2O})+(m_{EtOH}*spheat_{EtOH}*temp_{EtOH})}{(m_{H2O}*spheat_{H2O})+(m_{EtOH}*spheat_{EtOH})}$ where spheat is specific heat.

Filling that horrifying-looking formula in with some values:

$16.0=\frac{(x*4182*20.0)+(.1200*2440*10.0)}{(x*4182)+(.1200*2440)}$ and

$16.0=\frac{83640x+2928}{4182x+292.8}$ and

16(4182x + 292.8) = 83640x + 2928 and

66912x + 4684.8 = 83640x + 2928 and

1756.8 = 16728x so

x = .105 kg and the amount of water added is 105 g

4 0

3 years ago

A mass of 8 kg moves at a rate of 14.3 m/sec. what is the KE developed by the mass?

Lynna [10]

Kinetic energy is the energy associated with the motion of an object. It's a scalar quantity, there is no direction associated with KE and it has no components. $KE = \frac{mv ^{2} }{2} = \frac{8 *14.3 ^{2} }{2} = 4 *204.49 = 817.96J$ . Therefore Kinetic energy is 817.96J.

6 0

3 years ago