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2 years ago

PLEASE HELP FOR PHYSICS!

Physics

1 answer:

Stolb23 [73]2 years ago

8 0

Hi there!

Recall Newton's Law of Universal Gravitation:

$\large\boxed{F_g = G\frac{m_1m_2}{r^2}}$

Where:

Fg = Force of gravity (N)

G = Gravitational Constant

m1, m2 = masses of objects (kg)

r = distance between objects (m)

Plug in the given values stated in the problem:

$F_g = (6.673*10^{-11})\frac{50 * 50}{25^2} = \boxed{2.669 * 10^{-10} N}$

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A carton is given a push across a horizontal, frictionless surface. The carton has a mass m, the push gives it an initial speed

sammy [17]

Answer and Explanation:

Data provided in the question

Carbon mass = m

Initial speed = v_i

Coefficient = μk

Based on the above information, the expressions are as follows

a. By using the energy considerations the expression for the carton moving distance is

As we know that

$Fd = \frac{1}{2} m (v_i^2- v_f^2)$

where,

$v_f = 0$

$F = u_kmg$

$(\mu_kg) d = \frac{1}{2} m v_i^2$

$d = \frac{\frac{1}{2}v_i^2}{\mu_kg}$

$d = \frac{v_i^2}{2 \mu_kg}$

b. The initial speed of the carton if the factor of 3 risen, so the expression is

$v_i^1 = 3v_i$

$d^i = \frac{(3v_i^2)}{2\mu_kg}$

$= \frac{9v_i^2}{2\mu_kg}$

$d^i = 9(d)$

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4 years ago

A sensitive gravimeter at a mountain observatory finds that the free-fall acceleration is 0.0055 m/s2 less than that at sea leve

pshichka [43]

Gs*rs^2 = gm*rm^2
rm = rs*√gs/gm 
rm = 6370*√9.83/(9.83-0.009) = 6372.92 
mountain observatory is placed at an altitude worth 2920 m asl

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7 0

4 years ago

3)A mass of 4 kg rests on a horizontal plane. The plane is gradually inclined until at an angle o=15° with the horizontal, the m

Veronika [31]

Answer:

A mass of 4 Kg rest on the horizontal plane. The plane is gradually inclined until at an angle of θ=15

∘

with the horizontal,the mass just being to slide what is the coffeficient of static friction between the block & the surface.

Explanation:

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3 years ago

According to the law of conservation of energy, which statement must be