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3 years ago

What is an observation in an experiment ?

1 answer:

4 0

In science, observation can also involve the recording of data via the use of scientific instruments. The term may also refer to any data collected during the scientific activity.

Hope this helps,

kwrob

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Calculate curls of the following vector functions (a) AG) 4x3 - 2x2-yy + xz2 2

aleksandr82 [10.1K]

Answer:

The curl is $0 \hat x -z^2 \hat y -4xy \hat z$

Explanation:

Given the vector function

$\vec A (\vec r) =4x^3 \hat{x}-2x^2y \hat y+xz^2 \hat z$

We can calculate the curl using the definition

$\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\A_x&X_y&A_z\end{array}\right|$

Thus for the exercise we will have

$\nabla \times \vec A (\vec r ) = \left|\begin{array}{ccc}\hat x&\hat y&\hat z\\\partial/\partial x&\partial/\partial y&\partial/\partial z\\4x^3&-2x^2y&xz^2\end{array}\right|$

So we will get

$\nabla \times \vec A (\vec r )= \left( \cfrac{\partial}{\partial y}(xz^2)-\cfrac{\partial}{\partial z}(-2x^2y)\right) \hat x - \left(\cfrac{\partial}{\partial x}(xz^2)-\cfrac{\partial}{\partial z}(4x^3) \right) \hat y + \left(\cfrac{\partial}{\partial x}(-2x^2y)-\cfrac{\partial}{\partial y}(4x^3) \right) \hat z$

Working with the partial derivatives we get the curl

$\nabla \times \vec A (\vec r )=0 \hat x -z^2 \hat y -4xy \hat z$

6 0

3 years ago

Why do Sesame Oil and Dr Pepper react in a exploding soda? Just like Diet Coke and Mentos.

galben [10]

Its the compounds inside both liquids that react to eachother negativly idk how else to put it

8 0

3 years ago

Evaluate the importance of having a control group in a scientific investigation. help plzzz

olganol [36]

The importance of having a control group is to see how much your other test subjects changed. You use the control to compare.

7 0

3 years ago

An object travels along a straight line across a horizontal surface, and its motion is described by the velocity versus time gra

Mkey [24]

Answer:

C.)Finding the area bound by the horizontal axis and the curve from 0 s to 5 s

D.)Using Average Speed = total distance/total and multiplying the average speed of 5m/s by a total time of 5 s

Explanation:

The graph seems to be missing, however we can still answer the question.

In fact, we have to keep in mind the following facts:

- In a velocity-time graph, the area under the curve represents the displacement of the object, while the slope of the curve corresponds to its acceleration.

From this, we can already say that the following option:

C.)Finding the area bound by the horizontal axis and the curve from 0 s to 5 s

is correct, while the statement

A.)Finding the slope of the line between 0 s to 5 s

is wrong.

Moreover, the average speed of an object in motion is given by

$v=\frac{d}{t}$

where d is the total distance covered while t is the total time taken. Once we have calculated the average speed, the total displacement over a certain time period can be simply calculated by multiplying the average speed by the time interval: so, the option

D.)Using Average Speed = total distance/total and multiplying the average speed of 5m/s by a total time of 5 s

is also correct.

The last option remained:

B.)Dividing the change in velocity between 0 s to 5 s by the change in time

is wrong, because in this way we are calculating the acceleration, not the displacement.

6 0

3 years ago

A car sits in an entrance ramp to a freeway, waiting for a break in the traffic. The driver sees a small gap between a van and a

klio [65]

So what we can do is use the next formula
(Vf)^2=(Vo)^2+2ad
So when we replace the data into the formula it goes (25)^2 = o^2 + 2(129)a
625 = 258a
a = 2.42 distance/time/time

I hope this helps you

8 0

3 years ago