Calculate the volume of air in liters that you might inhale (and exhale) in 12.0 hours. Assume that each breath has a volume of
1 answer:
Taking into account the rule of three, the volume of air that you inhale (and exhale) in 12.0 hours is 4,384.8 liters.
<h3>Rule of three</h3>In first place, the rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.
That is, what is intended with it is to find the fourth term of a proportion knowing the other three.
If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied.
To solve a direct rule of three, the following formula must be followed, being a, b and c known data and x the variable to be calculated:
a ⇒ b
c ⇒ x
So:
To calculated the volume of air inhaled and exhaled in 12 hours, you know that each breath has a volume of 0.435 liters, and that you are breathing 14 times a minute.
The you can apply the following rule of three: If each breath has a volume of 0.435 liters, 14 breaths have how much volume?
<u><em>volume= 6.09 liters</em></u>
So, 14 breaths a minute have a volume of 6.09 liters, this means that in 1 minute you inhale and exhale 6.09 liters.
Now, knowing that 1 hour has 60 minutes, 12 hours has 720 minutes. So you can apply the following rule of three: in 1 minute you inhale and exhale 6.09 liters, in 720 minutes you inhale and exhale how much volume?
<u><em>volume= 4,384.8 liters</em></u>
In summary, the volume of air that you inhale (and exhale) in 12.0 hours is 4,384.8 liters.
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Answer:
The volume in the first tank = 0.32
The volume in the second tank = 2.066
The final pressure of the mixture = 203.64 K pa
Explanation:
<u>First Tank </u>
Mass = 2 kg
Pressure = 550 k pa
Temperature = 25 °c = 298 K
Gas constant for nitrogen = 0.297
From the ideal gas equation
P V = m R T
550 × V = 2 × 0.297 × 298
V = 0.32
This is the volume in the first tank.
<u>Second tank</u>
Mass = 4 kg
Pressure = 150 K pa
Temperature = 25 °c = 298 K
Gas constant for oxygen = 0.26
From the ideal gas equation
P V = m R T
150 × V = 4 × 0.26 × 298
V = 2.066
This is the volume in the second tank.
This is the iso thermal mixing. i.e.
----- (1)
Put this value in equation (1)
× 2.386 = 550 × 0.32 + 150 × 2.066
= 203.64 K pa
Therefore the final pressure of the mixture = 203.64 K pa
Alkaline earth metal are the elements present in II group in the periodic table and are known as 'Metals' and have a charge of +2.
Alkaline earth metals - Be , Mg Ca, Sr , Ba, Ra
Halogens are present in VII A group in the periodic table and are 'Non-metals' and have a charge of -1.
Halogens - F, Cl, Br, I, At
When Alkaline earth metal (metals) combine with Halogens (non-metals) the compound formed will be ionic compound and the formula of the compound will be based on the charges of the element.
When we write the formula of the ionic compound the charges of the elements get criss crossed.
For example - Mg (Alkaline earth metal) have a charge of +2 and Cl (Halogen) have a charge of -1 and when they combine to form the formula their charges get criss crossed and we will get or
When an alkaline earth metal, A, reacts with a halogen, X, the formula of the Ionic compound formed should be
