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horrorfan [7]
3 years ago
10

Edge 2020 waves and diffraction lab report d a t a ​

Physics
2 answers:
Andreyy893 years ago
8 0

Answer:

Explanation:

Waves and Diffraction: Lab ReportTitle:Lab: Waves and DiffractionPurpose:When a wave encounters a small obstacle or the edge of a barrier, the phenomenon known asdiffraction will occur. The wave theory of light can help explain diffraction, although observingdiffraction of light directly is difficult due to the very short wavelengths of light. In this lab, you willuse a “ripple tank” simulation, which provides a convenient way to study wave diffraction on alarger scale, since the principles of wave diffraction apply to physical waves (such as soundwaves and waves in liquid) as well as electromagnetic waveswaves

Sever21 [200]3 years ago
5 0

Answer:Theoretical Discussion

The diffraction of classical waves refers to the phenomenon wherein the waves encounter an obstacle that fragments the wave into components that interfere with one another. Interference simply means that the wave fronts add together to make a new wave which can be significantly different than the original wave. For example, a pair of sine waves having the same amplitude, but being 180◦ out of phase will sum to zero, since everywhere one is positive, the other is negative by an equal amount.

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a student claims that since the model of the atom has been changed so many times, that means it is a weak model. State whether y
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Read 2 more answers
PLEASE HELP !!!
emmainna [20.7K]

Answer and Explanation:

The answer is <u>D) Alpha and Gamma</u>

Gamma radiation does not cause transmutations.

A <u>transmutation</u> is the <u>conversion of an atom of one element to an atom of another. This generally occurs through nuclear reacting.</u>

There are three main types of radiation: alpha, beta, and gamma. Both beta and alpha decay cause changes to the mass and atomic numbers. This results in a transmutation. Gamma radiation, however, does not.

Gamma radiation is the result of a gamma ray. In essence, the nucleus emits a high-energy proton. This is very penetrating and can only be stopped by aluminum, lead, soil, water, and concrete. This type of radiation does not change the element and, therefore, does not cause a transmutation.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

3 0
3 years ago
suppose that the man pictured on the front side is orbiting the earth (mass=5.98 x 10^24kg at a distance of 310 miles above the
wlad13 [49]

Answer:

a = 9.81[m/s^2]; v = 18683.5[m/s]

Explanation:

The stament of the problem is:

Suppose that the man pictured on the front side is orbiting the earth (mass = 5.98 x 1024kg) at a distance of 310 miles (1600 meters = 1 mile) above the surface of the earth (radius = 4000 miles).

a. What acceleration does he experience due to the earth's pull?

b. What tangential velocity must he possess in order that he orbit safely (in m/s)?

First we need to convert all the initial data to units of the SI

Rs = 310 [mil] = 498897 [m]

RT= 400 [mil] = 643738 [m]

r = Rs + RT = 1142635 [m] "distance from the center of the earth to the man"

F=G*\frac{M*m}{r^{2} } \\where:\\

G = universal gravitational constant

M = mass of the earth [kg]

m = mass of the man [kg]

r = distance from the center of the earth to the man [m]

a)

The acceleration he is experimenting is the same acceleration given by the gravity, therefore:

a = g = 9.81[m/s^2]

b)

To find the tangential velocity, we must determinate the force exerted by the earth.

Now we will find the force exerted by the gravity when the man is orbiting the earth at distance r.

G = 6.67*10^{-11} [\frac{N*m^{2} }{kg^{2} } ]\\M=5.98*10^{24}[kg]\\ m=100 [kg]\\Replacing:\\F = G*\frac{M*m}{r^{2} }

F = 6.67*10^{-11}*\frac{5.98*10^{24}*100 }{1142635^{2} } \\ F= 30550 [N]

And this force will be equal to the following expression:

F = m*\frac{v^{2} }{r} \\where:\\v= tangential velocity [m/s]\\v=\sqrt{\frac{F*r}{m} } \\v=\sqrt{\frac{30550*1142635}{100} } \\v=18683.5[m/s]

8 0
3 years ago
Receiver maxima problem. When the receiver moves through one cycle, how many maxima of the standing wave pattern does the receiv
shusha [124]

Answer:

Two.

Explanation:

  • A standing wave or stationary wave are the type of wave in which it oscillates with time but the amplitude does not move.
  • One complete wave consists of two loops.
  • It means that when the receiver moves through one cycle, two maxima of standing wave pattern the receiver pass through.
8 0
3 years ago
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