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MrMuchimi
2 years ago
6

An inventor is applying for a patent. He claims his new heat engine can produce 1,200 J of work for every 1,800 J of heat applie

d to it. In 3-5 sentences evaluate this claim after solving for n. ​
Physics
1 answer:
Marat540 [252]2 years ago
5 0

The efficiency of the heat engine is 66.67%.

<h3>Efficiency of the heat engine</h3>

The efficiency of the heat energy is determined by taking the ratio of the output energy to input energy as shown below;

\eta = \frac{0utput \ energy}{1nput \ energy} = \frac{1200}{1800} \times 100\% = 66.67\%

<h3 /><h3>Evaluation of the claim</h3>

The efficiency of the heat engine is greater than 50% but less than 75% and can be considered to be moderately efficient.

This implies that the heat engine can convert up-to two-third of the input energy into useful energy.

Learn more about efficiency here: brainly.com/question/15418098

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The angular momentum of an object is equal to the product of its moment of inertia and angular velocity.
L = Iω
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ω = 2π/t
ω = 2π/0.3
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L = 1.3 x 20.9
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3 years ago
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In order to find total magnification of a microscope, you need to multiply the power of eyepiece and objective lens.

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3 years ago
A devout halloweener not only dressed as an astronaut, but travelled to the moon for the full experience. The astronaut jumps on
nikdorinn [45]

Answer:

2.78 m

Explanation:

At the peak, the velocity is 0.

Given:

a = -1.6 m/s²

v₀ = 2.98 m/s

v = 0 m/s

x₀ = 0 m

Find:

x

v² = v₀² + 2a(x - x₀)

(0 m/s)² = (2.98 m/s)² + 2(-1.6 m/s²) (x - 0 m)

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Rounded to 3 sig-figs, the astronaut halloweener reaches a maximum height of 2.78 meters.

5 0
3 years ago
Describe how electricity flows through a simple closed circuit.
Vedmedyk [2.9K]

Answer:

Electrons are drawn from one end of the battery to the other. Connecting two of those ends allows an electric current to flow between them. Wires make a path through that current can flow from one end of a battery to the other end, which would be considered as: The north and east side

8 0
3 years ago
The frequency of a physical pendulum comprising a nonuniform rod of mass 1.15 kg pivoted at one end is observed to be 0.658 Hz.
S_A_V [24]

Answer:

The rotational inertia of the pendulum around its pivot point is 0.280\,kg\cdot m^{2}.

Explanation:

The angular frequency of a physical pendulum is measured by the following expression:

\omega = \sqrt{\frac{m\cdot g \cdot d}{I_{o}} }

Where:

\omega - Angular frequency, measured in radians per second.

m - Mass of the physical pendulum, measured in kilograms.

g - Gravitational constant, measured in meters per square second.

d - Straight line distance between the center of mass and the pivot point of the pendulum, measured in meters.

I_{O} - Moment of inertia with respect to pivot point, measured in kg\cdot m^{2}.

In addition, frequency and angular frequency are both related by the following formula:

\omega =2\pi\cdot f

Where:

f - Frequency, measured in hertz.

If f = 0.658\,hz, then angular frequency of the physical pendulum is:

\omega = 2\pi \cdot (0.658\,hz)

\omega = 4.134\,\frac{rad}{s}

From the formula for the physical pendulum's angular frequency, the moment of inertia is therefore cleared:

\omega^{2} = \frac{m\cdot g \cdot d}{I_{o}}

I_{o} = \frac{m\cdot g \cdot d}{\omega^{2}}

Given that m = 1.15\,kg, g = 9.807\,\frac{m}{s^{2}}, d = 0.425\,m and \omega = 4.134\,\frac{rad}{s}, the moment of inertia associated with the physical pendulum is:

I_{o} = \frac{(1.15\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.425\,m)}{\left(4.134\,\frac{rad}{s} \right)^{2}}

I_{o} = 0.280\,kg\cdot m^{2}

The rotational inertia of the pendulum around its pivot point is 0.280\,kg\cdot m^{2}.

8 0
3 years ago
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