Moles= mass divided by Molecular mass
Moles= 251.4 divided by 84
Moles=2.99
Rounded up is 3
The numbers inside the boxes represent the atomic number. the circles and dots represent the shells and electrons.
Answer : The number of moles of ions form are, and there are 3 ions formed.
Explanation :
First we have to calculate the moles of calcium iodide.
Molar mass of calcium iodide = 293.9 g/mol
Mass of calcium iodide = 51.0 g
Now we have to calculate the number of moles of ions.
As we know that when calcium iodide dissolved in water then it dissocites to give calcium ion and iodide ion.
The balanced chemical reaction will be:
From this we conclude that there are 3 ions formed.
As, 1 mole of calcium iodide dissociate to give number of ions
So, 0.174 mole of calcium iodide dissociate to give number of ions
Thus, the number of moles of ions form are,
Conc = moles / Vol you have C but need to find moles
moles KCl = mass / molar mass
25 g / 74.55 g,p;
0.335 moles
So rearrange the formula to find volume. Vol = moles / Conc
0.335 moles / 0.750 mol / L = 0.447 L or 447 mL
The answer in this question is 447 mL.
Answer:
Percent yield = 89.1%
Explanation:
Based on the equation:
Cl₂ + 2KI → 2KCl + I₂
<em>1 mole of Cl₂ reacts with 2 moles of KI to produce to moles of KCl</em>
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To solve this quesiton we must find the moles of each reactant in order to find the limiting reactant. With the limiting reactant we can find the moles of KCl and the mass:
<em>Moles Cl₂:</em>
8x10²⁵ molecules * (1mol / 6.022x10²³ molecules) = 133 moles
<em>Moles KI -Molar mass: 166.0028g/mol-</em>
25g * (1mol / 166.0028g) = 0.15 moles
Here, clarely, the KI is the limiting reactant
As 2 moles of KI produce 2 moles of KCl, the moles of KCl produced are 0.15 moles. The theoretical mass is:
0.15 moles * (74.5513g / mol) =
11.2g KCl
Percent yield is: Actual yield (10.0g) / Theoretical yield (11.2g) * 100
<h3>Percent yield = 89.1%</h3>