3 years ago

How to calculate t in shm when you have displacement.

Physics

1 answer:

sukhopar [10]3 years ago

6 0

Answer:

ikd

Explanation:

I don't get what your asking pls make it more clear

You might be interested in

A 1500 kg car is pushing a 4000 kg truck. The car and truck are accelerating at 2.0 m/s^2. Assuming that the frictional force on

Crazy boy [7]

To solve this problem we will use the Force equation according to the definition given in Newton's second law. There we have that the Force is equal to

$F =ma$

Where,

m = mass

a = acceleration

Our values are given as

$m_1 = 1500 kg$

$m_2 = 4000 kg$

$a = 2.0 m/s^2$

Considering that both mass are equal to one, we have that:

$F = (m_1+m_2)* a$

$F = (1500 + 4000)(2.0)$

$F = 11000 N = 11kN$

Therefore the truck exert a force on the car of 11kN

7 0

3 years ago

A myopic (nearsighted) lawyer has a far point of 60.0 cm. What is the diopter value of suitable corrective contacts?

Vlada [557]

Answer:

P = -1.67 dP

Explanation:

given,

myopic lawyer has a far point of = 60.0 cm = 0.6 m

If a person is suffering from myopia then he cannot see the farthest object clearly.

Image of far object does not form on the retina so, the image appear to be blur.

using lens formula

$\dfrac{1}{v}-\dfrac{1}{u} = \dfrac{1}{f}$

$-\dfrac{1}{0.6} = \dfrac{1}{f}$

$\dfrac{1}{f} =P$

$P = -\dfrac{1}{0.6}$

P = -1.67 dP

6 0

3 years ago

Why are more firefighters needed to help hold the fire hose when the increase of water flow increases the force of the water?

kondaur [170]

they are needed to withstand the recoil as tons of water are ejectedd at high speed ... like a cannon

6 0

3 years ago

Read 2 more answers

A 250 kg motorcycle starts at rest at a stoplight. When the light turns green the motorcycle accelerates to 20 m/s in 4 seconds.

aliya0001 [1]

F=MA
F + 200= 250 x 4
F + 200 = 1000
F= 1000-200
F= 800

6 0

4 years ago

4) The components of Vector A are given as follows Ax = -2.4 Ay = + 3.8 What is the magnitude of the A, and what is the angle th

Monica [59]

Answer:

A = 4.49

α = 57.72°

Explanation:

Knowing the magnitude of x & y of a vector we can determine the total magnitude of a vector.

$A=\sqrt{A_{x}^{2} +A_{y}^{2} } \\A=\sqrt{(2.4)^{2} +(3.8)^{2} }\\A=4.49$

The angle tangent can be used to determine the angle.

$tan(\alpha )=\frac{3.8}{2.4}\\tan(\alpha ) =1.5833\\\alpha =tan^{-1}(1.5833) \\\alpha = 57.72 (deg)$

5 0

3 years ago