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Likurg_2 [28]
3 years ago
12

Salicylamide can undergo an iodination by electrophilic aromatic substitution. Arrange the procedural steps in order to iodinate

salicylamide.
Chemistry
1 answer:
Tanzania [10]3 years ago
4 0

The procedural steps in order to get iodinate salicylamide are as follows:

  • It begins first at a laboratory.
  • Secondly, one has to dissolve salicylamide in ethanol.
  • Then one has to add sodium iodide.
  • Later on, one has to add sodium hypochlorite to the ice cold solution of salicylamide and sodium iodide.
  • Thereafter one has to sodium thiosulfate.
  • It is better to Acidify by a person adding about 10% of  HCl.
  • The one has to collect the crude product through the use of vacuum filtration.
  • Lastly one then Recrystallize from hot ethanol.
<h3>What is Electrophilic aromatic substitution?</h3>

The Electrophilic aromatic substitution is known to be a kind of an organic reaction where an atom is said to be added or attached to a kind of aromatic structure (that is made up of hydrogen) is said to be replaced by an electrophile.

Learn more about  electrophilic aromatic substitution from

brainly.com/question/14908357

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To what temperature must a balloon, initially at 25°C and 2.00 L, be heated in order to have a volume of 6.00 L
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Answer:

894 deg K

Explanation:

The computation is shown below:

Given that

V1 denotes the initial volume of gas = 2.00 L  

T1 denotes the initial temperature of gas = 25 + 273 = 298 K  

V2 denotes the final volume of gas  = 6.00 L  

T2 = ?

Based on the above information

Here we assume that the pressure is remain constant,

So,  

V1 ÷ T1 = V2 ÷ T2  

T2 = T1 × V2 ÷ V1

= (298)(6) ÷ (2)

= 894 deg K

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There are 3.45 moles of (NH4)2 SO4, how many grams is this?
blsea [12.9K]

Answer:

455.4 g

Explanation:

Data given:

no. of moles of (NH₄)₂SO₄= 3.45 mol

mass of (NH₄)₂SO₄ = ?

Solution

Formula will be used

           no.of moles = mass in grams / molar mass

Rearrange the above equation for mass

           mass in grams = no. of moles x molar mass . . . . . . . . (1)

molar mass of (NH₄)₂SO₄

molar mass of (NH₄)₂SO₄ = 2(14 + 4(1)) + 32 + 4(16)

molar mass of (NH₄)₂SO₄ = 2 (14 +4) + 32 + 64  

molar mass of (NH₄)₂SO₄ = 2 (18) + 32 + 64

molar mass of (NH₄)₂SO₄ = 36 + 32 + 64 = 132 g/mol

Put values in equation 1

           mass in grams = 3.45 mole x 132 g/mol

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So,

mass of (NH₄)₂SO₄ = 455.4 g

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