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Likurg_2 [28]
2 years ago
12

Salicylamide can undergo an iodination by electrophilic aromatic substitution. Arrange the procedural steps in order to iodinate

salicylamide.
Chemistry
1 answer:
Tanzania [10]2 years ago
4 0

The procedural steps in order to get iodinate salicylamide are as follows:

  • It begins first at a laboratory.
  • Secondly, one has to dissolve salicylamide in ethanol.
  • Then one has to add sodium iodide.
  • Later on, one has to add sodium hypochlorite to the ice cold solution of salicylamide and sodium iodide.
  • Thereafter one has to sodium thiosulfate.
  • It is better to Acidify by a person adding about 10% of  HCl.
  • The one has to collect the crude product through the use of vacuum filtration.
  • Lastly one then Recrystallize from hot ethanol.
<h3>What is Electrophilic aromatic substitution?</h3>

The Electrophilic aromatic substitution is known to be a kind of an organic reaction where an atom is said to be added or attached to a kind of aromatic structure (that is made up of hydrogen) is said to be replaced by an electrophile.

Learn more about  electrophilic aromatic substitution from

brainly.com/question/14908357

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the copper anode is weighed before and after the electrolysis reation. if the copper anode is not completely dry when it is weig
Dmitrij [34]

Answer:

Faraday's constant will be smaller than it is supposed to be.

Explanation:

If the copper anode was not completely dry when its mass was measured, mass of the copper must be heavier than it should have been. Hence, the calculated Faraday’s constant would be smaller than it is supposed to be since when calculating Faraday’s Constant, the charge transferred is divided by the moles of electrons.

5 0
3 years ago
A sample of gas has a volume of 12.0 L and a pressure of 2.00 ATM. If the pressure of gas is increased to6.00 ATM, what is the n
earnstyle [38]

Answer:

4L

Explanation:

8 0
3 years ago
Using the combined gas law, if the volume of a gas at 155kPa changes from 22L to 10L. What is the new pressure if the temperatur
Deffense [45]

Answer:

The answer to your question is  P2 = 342 kPa

Explanation:

Data

Pressure 1 = P1 = 155 kPa

Volume 1 = V1 = 22 l

Pressure 2 = P2 = ?

Volume 2 = V2 = 10 l

Temperature = constant

Process

1.- Write the equation of the combined gas law

                 P1V1/T1 = P2V2/ T2

Cancel T1 and T2 because they measure the same

                 P1V1 = P2V2

-Solve for P2

                 P2 = P1V1/V2

2.- Substitution

                 P2 = (155 x 22) / 10

3.- Simplification

                 P2 = 3410 / 10

4.- Result

                 P2 = 342 kPa

5 0
3 years ago
A 55.0 g piece of iron at 505 ° C is put into 735 grams of water at 15.0 ° C. What is the final temperature of the water and the
denpristay [2]

Answer:

It would be 95.3

Explanation:

4 0
4 years ago
A 5.00 mL sample of hydrochloric acid is titrated with 0.1293 M ammonia (a base). If the titration required 28.15 mL of ammonia,
Sladkaya [172]

Answer:

1. C = 0.73 M.

2. pH = 0.14

       

Explanation:

The reaction is the following:

HCl + NH₃ ⇄ NH₄⁺Cl⁻

From the titration, we can find the number of moles of HCl that were neutralized by the ammonia.

n_{a} = n_{b}

Where "a" is for acid and "b" is for base.

The number of moles is:

n = C*V  

Where "C" is for concentration and "V" for volume.

C_{a}V_{a} = C_{b}V_{b}

C_{a} = \frac{0.1293 M*28.15 mL}{5.00 mL} = 0.73 M

Hence the initial concentration of the acid is 0.73 M.

The original pH of the acid is given by:

pH = -log([H^{+}])

pH = -log(0.73) = 0.14          

Therefore, the original pH of the acid is 0.14.

I hope it helps you!                  

4 0
3 years ago
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