Answer:
Faraday's constant will be smaller than it is supposed to be.
Explanation:
If the copper anode was not completely dry when its mass was measured, mass of the copper must be heavier than it should have been. Hence, the calculated Faraday’s constant would be smaller than it is supposed to be since when calculating Faraday’s Constant, the charge transferred is divided by the moles of electrons.
Answer:
The answer to your question is P2 = 342 kPa
Explanation:
Data
Pressure 1 = P1 = 155 kPa
Volume 1 = V1 = 22 l
Pressure 2 = P2 = ?
Volume 2 = V2 = 10 l
Temperature = constant
Process
1.- Write the equation of the combined gas law
P1V1/T1 = P2V2/ T2
Cancel T1 and T2 because they measure the same
P1V1 = P2V2
-Solve for P2
P2 = P1V1/V2
2.- Substitution
P2 = (155 x 22) / 10
3.- Simplification
P2 = 3410 / 10
4.- Result
P2 = 342 kPa
Answer:
1. C = 0.73 M.
2. pH = 0.14
Explanation:
The reaction is the following:
HCl + NH₃ ⇄ NH₄⁺Cl⁻
From the titration, we can find the number of moles of HCl that were neutralized by the ammonia.

Where "a" is for acid and "b" is for base.
The number of moles is:
Where "C" is for concentration and "V" for volume.


Hence the initial concentration of the acid is 0.73 M.
The original pH of the acid is given by:
![pH = -log([H^{+}])](https://tex.z-dn.net/?f=%20pH%20%3D%20-log%28%5BH%5E%7B%2B%7D%5D%29%20)
Therefore, the original pH of the acid is 0.14.
I hope it helps you!