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djyliett [7]
2 years ago
10

Which of the following objects is in static equilibrium?

Physics
1 answer:
Likurg_2 [28]2 years ago
4 0
<h3><u>Answer:- </u></h3>

\longrightarrow \textsf{D. A bicycle sitting on the ground}

<h3><u>Solution</u>:-</h3>

<u>Let us check all options -</u>

  • A) An apple falling from a tree is under the influence of gravity. Thus some force is acting on the apple and it can not said to be in state of equilibrium.

  • B) A car moving at a constant velocity may said to be in state of equilibrium but the since the car is in motion ,equilibrium is dynamic in nature .Thus , it is not in static equilibrium.

  • C) A motorcycle speeding up has some acceleration due to some forces. Thus it can also not be said in state of static equilibrium.

  • D) Since the force acting on bicycle sitting down in zero as well as it is in state of rest , thus bicycle sitting on the ground may said to be in static equilibrium.

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Bingel [31]

Explanation:

According to the law of conservation of energy ,    

             Potential energy = kinetic energy

   mgh = \frac{1}{2} \times mv^{2} + \frac{1}{2} \times I \times \omega^{2}

                  I = \frac{mr^{2}}{2}

          \omega = \frac{v}{r}

     mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{2} \times (\frac{mr^{2}}{2}) \frac{v^{2}}{r^{2}}]

     mgh = [\frac{1}{2} \times mv^{2}] + [\frac{1}{4} \times mv^{2}]

             g \times h = \frac{3}{4} \times v^{2}

             9.8 \times 4.2 = \frac{3}{4} \times v^{2}

                  v = 7.4 m/s

thus, we can conclude that the translational speed of the cylinder when it leaves the incline is 7.4 m/s.

5 0
3 years ago
A block slides on a frictionless, horizontal surface with a speed of 1.32 m/s. The block encounters an unstretched spring and co
Rus_ich [418]

Answer:

Explanation:

The given time is 1 / 4 of the time period

So Time period  of oscillation.

= 4 x .4 =1.6 s

When the block reaches back its original position when it came in contact with the spring for the first time , the block and the spring will have maximum

velocity. After that spring starts unstretching , reducing its speed , so block loses contact as its velocity is not reduced .

So required velocity is the maximum velocity of the block while remaining in contact with the spring.

v ( max ) = w A = 1.32  m /s.

3 0
3 years ago
A uniform plane wave traveling in air is incident upon a flat, lossless, and infinite in extent dielectric interface with a diel
dexar [7]

Answer:

Check the explanation

Explanation:

Kindly check the attached images below to see the step by step explanation to the question above.

3 0
2 years ago
How tall would a tower need to be if the period of a pendulum were 30. seconds
Virty [35]
We use the following expression

T = 2*pi *sqrt(l/g)

Where T is the period of the pendulum

l is the length of the pendulum

and g the acceleration of gravity

We solve for l

l = [T/2*pi]² *g = [30s/2*pi]²* 9.8 [m/s²] = 223.413 m

The tower would need to be at least 223.413 m high
4 0
3 years ago
A person in the back of a pick-up moving at 20 m/s relative to the Earth, throws a baseball with a speed of 15 m/s in a directio
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Answer:

This is known as a Galilean transformation where

V' = V - U

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V - speed of object in the unprimed frame

U - speed of primed frame with respect to the unprimed frame

Here we have:

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So  V' = -15 - (-20) = 5 m/s

It may help if you draw a vector representing the moving frame and then add

a vector representing the speed of the ball in the moving frame.

3 0
3 years ago
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