At what temperature will 13.2 grams of neon gas occupy 12.30 liters at 1.95 atmospheres? Answer

Write or show a complete formation of the following ionic compounds <br>a)sodium oxide (Na2O)

OLga [1]

Answer:

Na + O2 -> Na2O

Explanation:

sodium has one atom, oxygen has two atoms and so they exchange atoms hence Sodium obtaining two atoms at the end of the formation

3 0

3 years ago

A 0.6-m3 rigid tank is filled with saturated liquid water at 135°C. A valve at the bottom of the tank is now opened, and one-hal

Lemur [1.5K]

The given question is incomplete. The complete question is as follows.

A 0.6-m3 rigid tank is filled with saturated liquid water at 135°C. A valve at the bottom of the tank is now opened, and one-half of the total mass is withdrawn from the tank in liquid form. Heat is transferred to water from a source of 210°C so that the temperature in the tank remains constant. Assume the surroundings to be at 25°C and 100 kPa. Determine the amount of heat transfer.

Explanation:

First, we will determine the initial mass from given volume and specific volume as follows.

$m_{1} = \frac{V}{\alpha_{1}}$

= $\frac{0.6}{0.001075}kg$

= 558.14 kg

Hence, the final mass and mass that has left the tank are as follows.

$m_{2} = m_{out} = \frac{1}{2}m_{1}$

= $\frac{1}{2} \times 558.14 kg$

= 279.07 kg

Now, the final specific volume is as follows.

$\alpha_{2} = \frac{V}{m_{2}}$

= $\frac{0.6}{279.07} m^{3}/kg$

= 0.00215 $m^{3}/kg$

Final quality of the mixture is determined actually from the total final specific volume and the specific volumes of the constituents for the given temperature are as follows.

$q_{2} = \frac{\alpha_{2} - \alpha_{liq135}}{(\alpha_{vap} - \alpha_{liq})_{135}}$

= $\frac{0.00215 - 0.001075}{0.58179 - 0.001075}$

= $1.85 \times 10^{-3}$

Hence, the final internal energy will be calculated as follows.

$u_{2} = u_{liq135} + q_{2}u_{vap135}$

= $(567.41 + 1.85 \times 10^{-3} \times 1977.3) kJ/kg$

= 571.06 kJ/kg

Now, we will calculate the heat transfer as follows.

$\Delta U = Q - m_{out}h_{out}$

$m_{2}u_{2} - m_{1}u_{1} = Q - m_{out}h_{out}$

Q = $(279.07 \times 571.06 - 558.14 \times 567.41 + 279.07 \times 567.75) kJ$

= 1113.5 kJ

Thus, we can conclude that amount of heat transfer is 1113.5 kJ.

6 0

3 years ago

Arrange the following elements in order of decreasing atomic radius: Ba, Sn, S, Pb, and As. Rank elements from largest to smalle

vodka [1.7K]

Answer:

Ba>Sn>Pb>As>S

Explanation:

Hello,

In this case, we can write the atomic radius for the given elements:

$r_{Ba}=268pm\\r_{Sn}=225pm\\r_{S}=100pm\\r_{Pb}=202pm\\r_{As}=185pm$

In such a way, the required order is:

Ba>Sn>Pb>As>S

This is also in agreement as a periodic trend which states that the higher the period, the higher the radius.

Regards.

8 0

3 years ago

What makes it possible to separate substances in a mixture?

Tanzania [10]

Answer:

I think D.

Explanation:

The substances in a mixture are separated by the differences in their physical properties, such as their particle size. The more different the properties are, the easier it is to separate the substances.

8 0

3 years ago

How many significant digits are in: 6.02 x 105

bija089 [108]

Answer: Number of Significant Figures: 3

The Significant Figures are 6 0 2

Explanation:

6.02 x10^5

Significant figures are the digits of a number that are meaningful in terms of accuracy or precision. They include:

Any non-zero digit

Zeros between non-zero digits as in 3003 or 45.60009

Trailing zeros only when there is a decimal point as in 6750. or 274.3300

5 0

2 years ago

At what temperature will 13.2 grams of neon gas occupy 12.30 liters at 1.95 atmospheres? Answer

At what temperature will 13.2 grams of neon gas occupy 12.30 liters at 1.95 atmospheres? Answer