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Valentin [98]
2 years ago
8

Which best describes deena’s error? the line for constant velocity is not horizontal; it is diagonal and slopes downward. the ar

ea of the rectangle and the triangle under the line should be added together for constant acceleration find acceleration by finding the area of the rectangle above the line. find velocity by calculating the slope of the line.
Physics
1 answer:
denis-greek [22]2 years ago
3 0

The statement best describes deena's error is: Find acceleration by finding the area of the rectangle above the line.

<h3>What is acceleration?</h3>

Acceleration is given by the ratio of Resultant or total force acting on any object and the its mass.

Deena made a chart to summarize features of a velocity vs. time graph for objects with constant acceleration and objects with constant velocity.

In the  velocity time graph, the area under the curve shows the displacement of the object and the slope represents the acceleration.

Thus, the deena's error is  Find acceleration by finding the area of the rectangle above the line.

Learn more about acceleration.

brainly.com/question/12550364

#SPJ1

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Write the formula used to calculate the weight of an object
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One possible formula is

<em>Weight = (mass of the object) x (acceleration of gravity where the object is).</em>


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Two basketballs of equal mass are rolling toward each other at constant velocities. The first basketball (B1) has a velocity of
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v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)

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Velocity of B₁ = 4.3m/s

Velocity of B₂ = -4.3m/s

For perfectly elastic collision:, momentum is conserved

m_1v_1 + m_2v_2 = m_1v'_1 + m_2v'_2

where,

m₁ = mass of Ball 1

m₂ = mass of Ball 2

v₁ = initial velocity of Ball 1

v₂ = initial velocity of ball 2

v'₁ = final velocity of ball 1

v'₂ = final velocity of ball 2

The final velocity of the balls after head on elastic collision would be

v'_2 = \frac{2m_1}{m_1+m_2} v_1 - \frac{m_1-m_2}{m_1+m_2} v_2\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} v_1 + \frac{2m_2}{m_1+m_2} v_2

Substituting the velocities in the equation

v'_2 = \frac{2m_1}{m_1+m_2} (4.3) - \frac{m_1-m_2}{m_1+m_2} (4.3)\\\\v'_1 = \frac{m_1-m_2}{m_1+m_2} (4.3) + \frac{2m_2}{m_1+m_2} (4.3)

If the masses of the ball is known then substitute the value in the above equation to get the final velocity of the ball.

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