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Nuetrik [128]
2 years ago
8

Question 4 of 25

Physics
1 answer:
Lyrx [107]2 years ago
5 0

Answer:

To check whether a chemical equation is balanced or not we usually look if elements on the product side are numerically equal to the reactant side or not.

A. Na + MgCl₂ → NaCl + Mg

<em> Reactant Product</em>

Na = 1 1

Mg = 1 1

Cl = 2 1

<u>Unb</u><u>alanced </u>

B. 2LiOH + H₂S → Li₂S + 2H₂O

<em>Reactant Product</em>

Li = 2 2

S = 1 1

O = 2 2

H = 4 4

<u>Balanced</u>

C. AgNO₃ + NaCl → NaNO₃ + AgCl

<em>Reactant Product</em>

Ag = 1 1

N = 1 1

Na = 1 1

Cl = 1 1

O = 3 3

<u>Balanced</u>

D. 3PBr₃ + 2Cl₂ → 3PCl₃ + 2Br₂

<em>Reactant Product</em>

P = 3 3

Br = 9 4

Cl = 4 9

<u>Unbalanced</u>

Therefore, equations B and C are balanced chemical equations.

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In the chemical equation above, the small number after the O in 1202 represent —
Murrr4er [49]

Answer:

G.) The number atoms of that element in the molecule

Explanation:

F is incorrect because the coefficient represents the amount of one type of molecule, not the subscript

G is correct because subscripts represent how many atoms of that element are present in that single molecule

H is incorrect because energy is not represented in this simple type of equation

J is incorrect because it doesn't even make sense

7 0
3 years ago
1. why did aristarchus choose the time of a half (quarter) moon to make his measurements for calculating the earth-sun distance?
Stells [14]

In order to make his measurements for determining the Earth-Sun distance, Aristarchus waited for the Moon's phase to be exactly half full while the Sun was still visible in the sky. For this reason, he chose the time of a half (quarter) moon.

<h3 /><h3>How did Aristarchus calculate the distance to the Sun?</h3>

It was now possible for another Greek astronomer, Aristarchus, to attempt to determine the Earth's distance from the Sun after learning the distance to the Moon. Aristarchus discovered that the Moon, the Earth, and the Sun formed a right triangle when they were all equally illuminated. Now that he was aware of the distance between the Earth and the Moon, all he needed to know to calculate the Sun's distance was the current angle between the Moon and the Sun. It was a wonderful argument that was weakened by scant evidence. Aristarchus calculated this angle to be 87 degrees using only his eyes, which was not far off from the actual number of 89.83 degrees. But when there are significant distances involved, even slight inaccuracies might suddenly become significant. His outcome was more than a thousand times off.

To know more about how Aristarchus calculate the distance to the Sun, visit:

brainly.com/question/26241069

#SPJ4

7 0
2 years ago
Your tired 10 lb. baby cousin is cradled in your arms as you're walking back and forth across a 15m room to get her to fall asle
Mashcka [7]

Work done = Force x Distance

Force = 10 lb = 44.5 N

Work Done = 44.5 N x 15 m

= 667.5 N-m

6 0
4 years ago
Which of the following is a composite of a gas and a solid
cricket20 [7]
<span>{c o {a la manzana o
<span>Vapor de agua en el aire en una ducha de agua caliente</span>
</span>

3 0
4 years ago
Please help.......
IceJOKER [234]

Answer:

(L: Length, T: Time)

p: Dimension: L; unit: m

q: Dimension: L/T or (L)*(T)^-1; unit: m/s

r: Dimension: L/T^2 or (L)*(T)^-2; unit: m/s^2

Explanation:

since y is distance (Length), make all terms L distance.

p is same as y dimension ==> dimension: L; unit: m (meter)

qt dimension is L ==>  q dimension :L/T; unit: m/s

rt^2 dimension is L ==> r dimension : L/T^2; unit: m/s^2

3 0
3 years ago
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